mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
171 lines
21 KiB
JSON
171 lines
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JSON
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"title": "Maximum Difference Between Increasing Elements",
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"content": "<p>Given a <strong>0-indexed</strong> integer array <code>nums</code> of size <code>n</code>, find the <strong>maximum difference</strong> between <code>nums[i]</code> and <code>nums[j]</code> (i.e., <code>nums[j] - nums[i]</code>), such that <code>0 <= i < j < n</code> and <code>nums[i] < nums[j]</code>.</p>\n\n<p>Return <em>the <strong>maximum difference</strong>. </em>If no such <code>i</code> and <code>j</code> exists, return <code>-1</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [7,<strong><u>1</u></strong>,<strong><u>5</u></strong>,4]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>\nThe maximum difference occurs with i = 1 and j = 2, nums[j] - nums[i] = 5 - 1 = 4.\nNote that with i = 1 and j = 0, the difference nums[j] - nums[i] = 7 - 1 = 6, but i > j, so it is not valid.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [9,4,3,2]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong>\nThere is no i and j such that i < j and nums[i] < nums[j].\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [<strong><u>1</u></strong>,5,2,<strong><u>10</u></strong>]\n<strong>Output:</strong> 9\n<strong>Explanation:</strong>\nThe maximum difference occurs with i = 0 and j = 3, nums[j] - nums[i] = 10 - 1 = 9.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 <= n <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "增量元素之间的最大差值",
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"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> ,该数组的大小为 <code>n</code> ,请你计算 <code>nums[j] - nums[i]</code> 能求得的 <strong>最大差值 </strong>,其中 <code>0 <= i < j < n</code> 且 <code>nums[i] < nums[j]</code> 。</p>\n\n<p>返回 <strong>最大差值</strong> 。如果不存在满足要求的 <code>i</code> 和 <code>j</code> ,返回 <code>-1</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>nums = [7,<em><strong>1</strong></em>,<em><strong>5</strong></em>,4]\n<strong>输出:</strong>4\n<strong>解释:</strong>\n最大差值出现在 i = 1 且 j = 2 时,nums[j] - nums[i] = 5 - 1 = 4 。\n注意,尽管 i = 1 且 j = 0 时 ,nums[j] - nums[i] = 7 - 1 = 6 > 4 ,但 i > j 不满足题面要求,所以 6 不是有效的答案。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>nums = [9,4,3,2]\n<strong>输出:</strong>-1\n<strong>解释:</strong>\n不存在同时满足 i < j 和 nums[i] < nums[j] 这两个条件的 i, j 组合。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong>nums = [<em><strong>1</strong></em>,5,2,<em><strong>10</strong></em>]\n<strong>输出:</strong>9\n<strong>解释:</strong>\n最大差值出现在 i = 0 且 j = 3 时,nums[j] - nums[i] = 10 - 1 = 9 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 <= n <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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