leetcode-problemset/leetcode-cn/originData/largest-merge-of-two-strings.json

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        "question": {
            "questionId": "1880",
            "questionFrontendId": "1754",
            "categoryTitle": "Algorithms",
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            "title": "Largest Merge Of Two Strings",
            "titleSlug": "largest-merge-of-two-strings",
            "content": "<p>You are given two strings <code>word1</code> and <code>word2</code>. You want to construct a string <code>merge</code> in the following way: while either <code>word1</code> or <code>word2</code> are non-empty, choose <strong>one</strong> of the following options:</p>\n\n<ul>\n\t<li>If <code>word1</code> is non-empty, append the <strong>first</strong> character in <code>word1</code> to <code>merge</code> and delete it from <code>word1</code>.\n\n\t<ul>\n\t\t<li>For example, if <code>word1 = &quot;abc&quot; </code>and <code>merge = &quot;dv&quot;</code>, then after choosing this operation, <code>word1 = &quot;bc&quot;</code> and <code>merge = &quot;dva&quot;</code>.</li>\n\t</ul>\n\t</li>\n\t<li>If <code>word2</code> is non-empty, append the <strong>first</strong> character in <code>word2</code> to <code>merge</code> and delete it from <code>word2</code>.\n\t<ul>\n\t\t<li>For example, if <code>word2 = &quot;abc&quot; </code>and <code>merge = &quot;&quot;</code>, then after choosing this operation, <code>word2 = &quot;bc&quot;</code> and <code>merge = &quot;a&quot;</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>Return <em>the lexicographically <strong>largest</strong> </em><code>merge</code><em> you can construct</em>.</p>\n\n<p>A string <code>a</code> is lexicographically larger than a string <code>b</code> (of the same length) if in the first position where <code>a</code> and <code>b</code> differ, <code>a</code> has a character strictly larger than the corresponding character in <code>b</code>. For example, <code>&quot;abcd&quot;</code> is lexicographically larger than <code>&quot;abcc&quot;</code> because the first position they differ is at the fourth character, and <code>d</code> is greater than <code>c</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> word1 = &quot;cabaa&quot;, word2 = &quot;bcaaa&quot;\n<strong>Output:</strong> &quot;cbcabaaaaa&quot;\n<strong>Explanation:</strong> One way to get the lexicographically largest merge is:\n- Take from word1: merge = &quot;c&quot;, word1 = &quot;abaa&quot;, word2 = &quot;bcaaa&quot;\n- Take from word2: merge = &quot;cb&quot;, word1 = &quot;abaa&quot;, word2 = &quot;caaa&quot;\n- Take from word2: merge = &quot;cbc&quot;, word1 = &quot;abaa&quot;, word2 = &quot;aaa&quot;\n- Take from word1: merge = &quot;cbca&quot;, word1 = &quot;baa&quot;, word2 = &quot;aaa&quot;\n- Take from word1: merge = &quot;cbcab&quot;, word1 = &quot;aa&quot;, word2 = &quot;aaa&quot;\n- Append the remaining 5 a&#39;s from word1 and word2 at the end of merge.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> word1 = &quot;abcabc&quot;, word2 = &quot;abdcaba&quot;\n<strong>Output:</strong> &quot;abdcabcabcaba&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word1.length, word2.length &lt;= 3000</code></li>\n\t<li><code>word1</code> and <code>word2</code> consist only of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "构造字典序最大的合并字符串",
            "translatedContent": "<p>给你两个字符串 <code>word1</code> 和 <code>word2</code> 。你需要按下述方式构造一个新字符串 <code>merge</code> ：如果 <code>word1</code> 或 <code>word2</code> 非空，选择 <strong>下面选项之一</strong> 继续操作：</p>\n\n<ul>\n\t<li>如果 <code>word1</code> 非空，将 <code>word1</code> 中的第一个字符附加到 <code>merge</code> 的末尾，并将其从 <code>word1</code> 中移除。\n\n\t<ul>\n\t\t<li>例如，<code>word1 = \"abc\" </code>且 <code>merge = \"dv\"</code> ，在执行此选项操作之后，<code>word1 = \"bc\"</code> ，同时 <code>merge = \"dva\"</code> 。</li>\n\t</ul>\n\t</li>\n\t<li>如果 <code>word2</code> 非空，将 <code>word2</code> 中的第一个字符附加到 <code>merge</code> 的末尾，并将其从 <code>word2</code> 中移除。\n\t<ul>\n\t\t<li>例如，<code>word2 = \"abc\" </code>且 <code>merge = \"\"</code> ，在执行此选项操作之后，<code>word2 = \"bc\"</code> ，同时 <code>merge = \"a\"</code> 。</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>返回你可以构造的字典序 <strong>最大</strong> 的合并字符串<em> </em><code>merge</code><em> 。</em></p>\n\n<p>长度相同的两个字符串 <code>a</code> 和 <code>b</code> 比较字典序大小，如果在 <code>a</code> 和 <code>b</code> 出现不同的第一个位置，<code>a</code> 中字符在字母表中的出现顺序位于 <code>b</code> 中相应字符之后，就认为字符串 <code>a</code> 按字典序比字符串 <code>b</code> 更大。例如，<code>\"abcd\"</code> 按字典序比 <code>\"abcc\"</code> 更大，因为两个字符串出现不同的第一个位置是第四个字符，而 <code>d</code> 在字母表中的出现顺序位于 <code>c</code> 之后。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = \"cabaa\", word2 = \"bcaaa\"\n<strong>输出：</strong>\"cbcabaaaaa\"\n<strong>解释：</strong>构造字典序最大的合并字符串，可行的一种方法如下所示：\n- 从 word1 中取第一个字符：merge = \"c\"，word1 = \"abaa\"，word2 = \"bcaaa\"\n- 从 word2 中取第一个字符：merge = \"cb\"，word1 = \"abaa\"，word2 = \"caaa\"\n- 从 word2 中取第一个字符：merge = \"cbc\"，word1 = \"abaa\"，word2 = \"aaa\"\n- 从 word1 中取第一个字符：merge = \"cbca\"，word1 = \"baa\"，word2 = \"aaa\"\n- 从 word1 中取第一个字符：merge = \"cbcab\"，word1 = \"aa\"，word2 = \"aaa\"\n- 将 word1 和 word2 中剩下的 5 个 a 附加到 merge 的末尾。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = \"abcabc\", word2 = \"abdcaba\"\n<strong>输出：</strong>\"abdcabcabcaba\"\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= word1.length, word2.length <= 3000</code></li>\n\t<li><code>word1</code> 和 <code>word2</code> 仅由小写英文组成</li>\n</ul>\n",
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                "Build the result character by character. At each step, you choose a character from one of the two strings.",
                "If the next character of the first string is larger than that of the second string, or vice versa, it's optimal to use the larger one.",
                "If both are equal, think of a criteria that lets you decide which string to consume the next character from.",
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