leetcode-problemset/leetcode-cn/originData/insert-interval.json

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            "categoryTitle": "Algorithms",
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            "title": "Insert Interval",
            "titleSlug": "insert-interval",
            "content": "<p>You are given an array of non-overlapping intervals <code>intervals</code> where <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> represent the start and the end of the <code>i<sup>th</sup></code> interval and <code>intervals</code> is sorted in ascending order by <code>start<sub>i</sub></code>. You are also given an interval <code>newInterval = [start, end]</code> that represents the start and end of another interval.</p>\n\n<p>Insert <code>newInterval</code> into <code>intervals</code> such that <code>intervals</code> is still sorted in ascending order by <code>start<sub>i</sub></code> and <code>intervals</code> still does not have any overlapping intervals (merge overlapping intervals if necessary).</p>\n\n<p>Return <code>intervals</code><em> after the insertion</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,3],[6,9]], newInterval = [2,5]\n<strong>Output:</strong> [[1,5],[6,9]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\n<strong>Output:</strong> [[1,2],[3,10],[12,16]]\n<strong>Explanation:</strong> Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= intervals.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>0 &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li><code>intervals</code> is sorted by <code>start<sub>i</sub></code> in <strong>ascending</strong> order.</li>\n\t<li><code>newInterval.length == 2</code></li>\n\t<li><code>0 &lt;= start &lt;= end &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "插入区间",
            "translatedContent": "<p>给你一个<strong> 无重叠的</strong><em> ，</em>按照区间起始端点排序的区间列表。</p>\n\n<p>在列表中插入一个新的区间，你需要确保列表中的区间仍然有序且不重叠（如果有必要的话，可以合并区间）。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,3],[6,9]], newInterval = [2,5]\n<strong>输出：</strong>[[1,5],[6,9]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\n<strong>输出：</strong>[[1,2],[3,10],[12,16]]\n<strong>解释：</strong>这是因为新的区间 <code>[4,8]</code> 与 <code>[3,5],[6,7],[8,10]</code> 重叠。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [], newInterval = [5,7]\n<strong>输出：</strong>[[5,7]]\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,5]], newInterval = [2,3]\n<strong>输出：</strong>[[1,5]]\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,5]], newInterval = [2,7]\n<strong>输出：</strong>[[1,7]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= intervals.length <= 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>0 <= intervals[i][0] <= intervals[i][1] <= 10<sup>5</sup></code></li>\n\t<li><code>intervals</code> 根据 <code>intervals[i][0]</code> 按 <strong>升序</strong> 排列</li>\n\t<li><code>newInterval.length == 2</code></li>\n\t<li><code>0 <= newInterval[0] <= newInterval[1] <= 10<sup>5</sup></code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {\n\n    }\n};",
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                    "code": "class Solution {\n    public int[][] insert(int[][] intervals, int[] newInterval) {\n\n    }\n}",
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                    "code": "class Solution(object):\n    def insert(self, intervals, newInterval):\n        \"\"\"\n        :type intervals: List[List[int]]\n        :type newInterval: List[int]\n        :rtype: List[List[int]]\n        \"\"\"",
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                    "code": "/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** insert(int** intervals, int intervalsSize, int* intervalsColSize, int* newInterval, int newIntervalSize, int* returnSize, int** returnColumnSizes) {\n    \n}",
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                    "code": "public class Solution {\n    public int[][] Insert(int[][] intervals, int[] newInterval) {\n\n    }\n}",
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                    "code": "/**\n * @param {number[][]} intervals\n * @param {number[]} newInterval\n * @return {number[][]}\n */\nvar insert = function(intervals, newInterval) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[][] $intervals\n     * @param Integer[] $newInterval\n     * @return Integer[][]\n     */\n    function insert($intervals, $newInterval) {\n\n    }\n}",
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                    "code": "class Solution {\n    fun insert(intervals: Array<IntArray>, newInterval: IntArray): Array<IntArray> {\n\n    }\n}",
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                    "code": "object Solution {\n    def insert(intervals: Array[Array[Int]], newInterval: Array[Int]): Array[Array[Int]] = {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn insert(intervals: Vec<Vec<i32>>, new_interval: Vec<i32>) -> Vec<Vec<i32>> {\n\n    }\n}",
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