mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
187 lines
24 KiB
JSON
187 lines
24 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "1000132",
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"questionFrontendId": "LCP 26",
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"categoryTitle": "Algorithms",
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"boundTopicId": 419869,
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"title": "导航装置",
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"titleSlug": "hSRGyL",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "导航装置",
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"translatedContent": "小扣参加的秋日市集景区共有 $N$ 个景点，景点编号为 $1$~$N$。景点内设有 $N-1$ 条双向道路，使所有景点形成了一个二叉树结构，根结点记为 `root`，景点编号即为节点值。\r\n\r\n由于秋日市集景区的结构特殊，游客很容易迷路，主办方决定在景区的若干个景点设置导航装置，按照所在景点编号升序排列后定义装置编号为 1 ~ M。导航装置向游客发送数据，数据内容为列表 `[游客与装置 1 的相对距离,游客与装置 2 的相对距离,...,游客与装置 M 的相对距离]`。由于游客根据导航装置发送的信息来确认位置，因此主办方需保证游客在每个景点接收的数据信息皆不相同。请返回主办方最少需要设置多少个导航装置。\r\n\r\n**示例 1：**\r\n>输入：`root = [1,2,null,3,4]`\r\n>\r\n>输出：`2`\r\n>\r\n>解释：在景点 1、3 或景点 1、4 或景点 3、4 设置导航装置。\r\n>\r\n>{:height=\"250px\"}\r\n\r\n\r\n\r\n**示例 2：**\r\n>输入：`root = [1,2,3,4]`\r\n>\r\n>输出：`1`\r\n>\r\n>解释：在景点 3、4 设置导航装置皆可。\r\n>\r\n>{:height=\"200px\"}\r\n\r\n\r\n\r\n**提示：**\r\n- `2 <= N <= 50000`\r\n- 二叉树的非空节点值为 `1~N` 的一个排列。\r\n",
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"difficulty": "Hard",
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"likes": 18,
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"username": "LeetCode",
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"name": "Tree",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode(int x) { val = x; }\n * }\n */\nclass Solution {\n public int navigation(TreeNode root) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\nclass Solution(object):\n def navigation(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: int\n \"\"\"",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\nclass Solution:\n def navigation(self, root: TreeNode) -> int:",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int x) { val = x; }\n * }\n */\npublic class Solution {\n public int Navigation(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val) {\n * this.val = val;\n * this.left = this.right = null;\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number}\n */\nvar navigation = function(root) {\n\n};",
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"lang": "TypeScript",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction navigation(root: TreeNode | null): number {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($value) { $this->val = $value; }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer\n */\n function navigation($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init(_ val: Int) {\n * self.val = val\n * self.left = nil\n * self.right = nil\n * }\n * }\n */\nclass Solution {\n func navigation(_ root: TreeNode?) -> Int {\n\n }\n}",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun navigation(root: TreeNode?): Int {\n\n }\n}",
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"lang": "Dart",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n int navigation(TreeNode? root) {\n\n }\n}",
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"lang": "Go",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc navigation(root *TreeNode) int {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val)\n# @val = val\n# @left, @right = nil, nil\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef navigation(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var _value: Int) {\n * var value: Int = _value\n * var left: TreeNode = null\n * var right: TreeNode = null\n * }\n */\nobject Solution {\n def navigation(root: TreeNode): Int = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn navigation(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {\n\n }\n}",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec navigation(Root :: #tree_node{} | null) -> integer().\nnavigation(Root) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec navigation(root :: TreeNode.t | nil) :: integer\n def navigation(root) do\n\n end\nend",
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