leetcode-problemset/leetcode-cn/originData/find-right-interval.json

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            "title": "Find Right Interval",
            "titleSlug": "find-right-interval",
            "content": "<p>You are given an array of <code>intervals</code>, where <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> and each <code>start<sub>i</sub></code> is <strong>unique</strong>.</p>\n\n<p>The <strong>right interval</strong> for an interval <code>i</code> is an interval <code>j</code> such that <code>start<sub>j</sub> &gt;= end<sub>i</sub></code> and <code>start<sub>j</sub></code> is <strong>minimized</strong>. Note that <code>i</code> may equal <code>j</code>.</p>\n\n<p>Return <em>an array of <strong>right interval</strong> indices for each interval <code>i</code></em>. If no <strong>right interval</strong> exists for interval <code>i</code>, then put <code>-1</code> at index <code>i</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,2]]\n<strong>Output:</strong> [-1]\n<strong>Explanation:</strong> There is only one interval in the collection, so it outputs -1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[3,4],[2,3],[1,2]]\n<strong>Output:</strong> [-1,0,1]\n<strong>Explanation:</strong> There is no right interval for [3,4].\nThe right interval for [2,3] is [3,4] since start<sub>0</sub> = 3 is the smallest start that is &gt;= end<sub>1</sub> = 3.\nThe right interval for [1,2] is [2,3] since start<sub>1</sub> = 2 is the smallest start that is &gt;= end<sub>2</sub> = 2.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,4],[2,3],[3,4]]\n<strong>Output:</strong> [-1,2,-1]\n<strong>Explanation:</strong> There is no right interval for [1,4] and [3,4].\nThe right interval for [2,3] is [3,4] since start<sub>2</sub> = 3 is the smallest start that is &gt;= end<sub>1</sub> = 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= intervals.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>-10<sup>6</sup> &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt;= 10<sup>6</sup></code></li>\n\t<li>The start point of each interval is <strong>unique</strong>.</li>\n</ul>\n",
            "translatedTitle": "寻找右区间",
            "translatedContent": "<p>给你一个区间数组 <code>intervals</code> ，其中&nbsp;<code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> ，且每个&nbsp;<code>start<sub>i</sub></code> 都 <strong>不同</strong> 。</p>\n\n<p>区间 <code>i</code> 的 <strong>右侧区间</strong> 可以记作区间 <code>j</code> ，并满足 <code>start<sub>j</sub></code><code>&nbsp;&gt;= end<sub>i</sub></code> ，且 <code>start<sub>j</sub></code> <strong>最小化 </strong>。注意 <code>i</code> 可能等于 <code>j</code> 。</p>\n\n<p>返回一个由每个区间 <code>i</code> 的 <strong>右侧区间</strong> 在&nbsp;<code>intervals</code> 中对应下标组成的数组。如果某个区间 <code>i</code> 不存在对应的 <strong>右侧区间</strong> ，则下标 <code>i</code> 处的值设为 <code>-1</code> 。</p>\n&nbsp;\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,2]]\n<strong>输出：</strong>[-1]\n<strong>解释：</strong>集合中只有一个区间，所以输出-1。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[3,4],[2,3],[1,2]]\n<strong>输出：</strong>[-1,0,1]\n<strong>解释：</strong>对于 [3,4] ，没有满足条件的“右侧”区间。\n对于 [2,3] ，区间[3,4]具有最小的“右”起点;\n对于 [1,2] ，区间[2,3]具有最小的“右”起点。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,4],[2,3],[3,4]]\n<strong>输出：</strong>[-1,2,-1]\n<strong>解释：</strong>对于区间 [1,4] 和 [3,4] ，没有满足条件的“右侧”区间。\n对于 [2,3] ，区间 [3,4] 有最小的“右”起点。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;=&nbsp;intervals.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>-10<sup>6</sup> &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt;= 10<sup>6</sup></code></li>\n\t<li>每个间隔的起点都 <strong>不相同</strong></li>\n</ul>\n",
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