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"categoryTitle": "Algorithms",
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"title": "Find if Path Exists in Graph",
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"content": "<p>There is a <strong>bi-directional</strong> graph with <code>n</code> vertices, where each vertex is labeled from <code>0</code> to <code>n - 1</code> (<strong>inclusive</strong>). The edges in the graph are represented as a 2D integer array <code>edges</code>, where each <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> denotes a bi-directional edge between vertex <code>u<sub>i</sub></code> and vertex <code>v<sub>i</sub></code>. Every vertex pair is connected by <strong>at most one</strong> edge, and no vertex has an edge to itself.</p>\n\n<p>You want to determine if there is a <strong>valid path</strong> that exists from vertex <code>source</code> to vertex <code>destination</code>.</p>\n\n<p>Given <code>edges</code> and the integers <code>n</code>, <code>source</code>, and <code>destination</code>, return <code>true</code><em> if there is a <strong>valid path</strong> from </em><code>source</code><em> to </em><code>destination</code><em>, or </em><code>false</code><em> otherwise</em><em>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/08/14/validpath-ex1.png\" style=\"width: 141px; height: 121px;\" />\n<pre>\n<strong>Input:</strong> n = 3, edges = [[0,1],[1,2],[2,0]], source = 0, destination = 2\n<strong>Output:</strong> true\n<strong>Explanation:</strong> There are two paths from vertex 0 to vertex 2:\n- 0 &rarr; 1 &rarr; 2\n- 0 &rarr; 2\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/08/14/validpath-ex2.png\" style=\"width: 281px; height: 141px;\" />\n<pre>\n<strong>Input:</strong> n = 6, edges = [[0,1],[0,2],[3,5],[5,4],[4,3]], source = 0, destination = 5\n<strong>Output:</strong> false\n<strong>Explanation:</strong> There is no path from vertex 0 to vertex 5.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= edges.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= u<sub>i</sub>, v<sub>i</sub> &lt;= n - 1</code></li>\n\t<li><code>u<sub>i</sub> != v<sub>i</sub></code></li>\n\t<li><code>0 &lt;= source, destination &lt;= n - 1</code></li>\n\t<li>There are no duplicate edges.</li>\n\t<li>There are no self edges.</li>\n</ul>\n",
"translatedTitle": "寻找图中是否存在路径",
"translatedContent": "<p>有一个具有 <code>n</code> 个顶点的 <strong>双向</strong> 图,其中每个顶点标记从 <code>0</code> 到 <code>n - 1</code>(包含 <code>0</code> 和 <code>n - 1</code>)。图中的边用一个二维整数数组 <code>edges</code> 表示,其中 <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> 表示顶点 <code>ui</code> 和顶点 <code>vi</code> 之间的双向边。 每个顶点对由 <strong>最多一条</strong> 边连接,并且没有顶点存在与自身相连的边。</p>\n\n<p>请你确定是否存在从顶点 <code>source</code> 开始,到顶点 <code>destination</code> 结束的 <strong>有效路径</strong> 。</p>\n\n<p>给你数组 <code>edges</code> 和整数 <code>n</code>、<code>source</code> 和 <code>destination</code>,如果从 <code>source</code> 到 <code>destination</code> 存在 <strong>有效路径</strong> ,则返回 <code>true</code>,否则返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/08/14/validpath-ex1.png\" style=\"width: 141px; height: 121px;\" />\n<pre>\n<strong>输入:</strong>n = 3, edges = [[0,1],[1,2],[2,0]], source = 0, destination = 2\n<strong>输出:</strong>true\n<strong>解释:</strong>存在由顶点 0 到顶点 2 的路径:\n- 0 → 1 → 2 \n- 0 → 2\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/08/14/validpath-ex2.png\" style=\"width: 281px; height: 141px;\" />\n<pre>\n<strong>输入:</strong>n = 6, edges = [[0,1],[0,2],[3,5],[5,4],[4,3]], source = 0, destination = 5\n<strong>输出:</strong>false\n<strong>解释:</strong>不存在由顶点 0 到顶点 5 的路径.\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= edges.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= u<sub>i</sub>, v<sub>i</sub> &lt;= n - 1</code></li>\n\t<li><code>u<sub>i</sub> != v<sub>i</sub></code></li>\n\t<li><code>0 &lt;= source, destination &lt;= n - 1</code></li>\n\t<li>不存在重复边</li>\n\t<li>不存在指向顶点自身的边</li>\n</ul>\n",
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