leetcode-problemset/leetcode-cn/originData/decrease-elements-to-make-array-zigzag.json

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        "question": {
            "questionId": "1247",
            "questionFrontendId": "1144",
            "categoryTitle": "Algorithms",
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            "title": "Decrease Elements To Make Array Zigzag",
            "titleSlug": "decrease-elements-to-make-array-zigzag",
            "content": "<p>Given an array <code>nums</code> of integers, a <em>move</em>&nbsp;consists of choosing any element and <strong>decreasing it by 1</strong>.</p>\n\n<p>An array <code>A</code> is a&nbsp;<em>zigzag array</em>&nbsp;if either:</p>\n\n<ul>\n\t<li>Every even-indexed element is greater than adjacent elements, ie.&nbsp;<code>A[0] &gt; A[1] &lt; A[2] &gt; A[3] &lt; A[4] &gt; ...</code></li>\n\t<li>OR, every odd-indexed element is greater than adjacent elements, ie.&nbsp;<code>A[0] &lt; A[1] &gt; A[2] &lt; A[3] &gt; A[4] &lt; ...</code></li>\n</ul>\n\n<p>Return the minimum number of moves to transform the given array <code>nums</code> into a zigzag array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We can decrease 2 to 0 or 3 to 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [9,6,1,6,2]\n<strong>Output:</strong> 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "递减元素使数组呈锯齿状",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code>，每次 <strong>操作</strong>&nbsp;会从中选择一个元素并 <strong>将该元素的值减少&nbsp;1</strong>。</p>\n\n<p>如果符合下列情况之一，则数组&nbsp;<code>A</code>&nbsp;就是 <strong>锯齿数组</strong>：</p>\n\n<ul>\n\t<li>每个偶数索引对应的元素都大于相邻的元素，即&nbsp;<code>A[0] &gt; A[1] &lt; A[2] &gt; A[3] &lt; A[4] &gt; ...</code></li>\n\t<li>或者，每个奇数索引对应的元素都大于相邻的元素，即&nbsp;<code>A[0] &lt; A[1] &gt; A[2] &lt; A[3] &gt; A[4] &lt; ...</code></li>\n</ul>\n\n<p>返回将数组&nbsp;<code>nums</code>&nbsp;转换为锯齿数组所需的最小操作次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,2,3]\n<strong>输出：</strong>2\n<strong>解释：</strong>我们可以把 2 递减到 0，或把 3 递减到 1。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [9,6,1,6,2]\n<strong>输出：</strong>4\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int movesToMakeZigzag(vector<int>& nums) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def movesToMakeZigzag(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: int\n        \"\"\"",
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                    "code": "int movesToMakeZigzag(int* nums, int numsSize) {\n    \n}",
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                    "code": "public class Solution {\n    public int MovesToMakeZigzag(int[] nums) {\n\n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @return {number}\n */\nvar movesToMakeZigzag = function(nums) {\n\n};",
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                    "lang": "Go",
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                    "code": "func movesToMakeZigzag(nums []int) int {\n\n}",
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                    "code": "# @param {Integer[]} nums\n# @return {Integer}\ndef moves_to_make_zigzag(nums)\n\nend",
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                "Do each case (even indexed is greater, odd indexed is greater) separately. In say the even case, you should decrease each even-indexed element until it is lower than its immediate neighbors."
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