leetcode-problemset/leetcode-cn/originData/decompress-run-length-encoded-list.json

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        "question": {
            "questionId": "1241",
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            "categoryTitle": "Algorithms",
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            "title": "Decompress Run-Length Encoded List",
            "titleSlug": "decompress-run-length-encoded-list",
            "content": "<p>We are given a list <code>nums</code> of integers representing a list compressed with run-length encoding.</p>\n\n<p>Consider each adjacent pair&nbsp;of elements <code>[freq, val] = [nums[2*i], nums[2*i+1]]</code>&nbsp;(with <code>i &gt;= 0</code>).&nbsp; For each such pair, there are <code>freq</code> elements with value <code>val</code> concatenated in a sublist. Concatenate all the sublists from left to right to generate the decompressed list.</p>\n\n<p>Return the decompressed list.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4]\n<strong>Output:</strong> [2,4,4,4]\n<strong>Explanation:</strong> The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2].\nThe second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4].\nAt the end the concatenation [2] + [4,4,4] is [2,4,4,4].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,2,3]\n<strong>Output:</strong> [1,3,3]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>nums.length % 2 == 0</code></li>\n\t<li><code><font face=\"monospace\">1 &lt;= nums[i] &lt;= 100</font></code></li>\n</ul>\n",
            "translatedTitle": "解压缩编码列表",
            "translatedContent": "<p>给你一个以行程长度编码压缩的整数列表 <code>nums</code> 。</p>\n\n<p>考虑每对相邻的两个元素 <code>[freq, val] = [nums[2*i], nums[2*i+1]]</code> （其中 <code>i >= 0</code> ），每一对都表示解压后子列表中有 <code>freq</code> 个值为 <code>val</code> 的元素，你需要从左到右连接所有子列表以生成解压后的列表。</p>\n\n<p>请你返回解压后的列表。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4]\n<strong>输出：</strong>[2,4,4,4]\n<strong>解释：</strong>第一对 [1,2] 代表着 2 的出现频次为 1，所以生成数组 [2]。\n第二对 [3,4] 代表着 4 的出现频次为 3，所以生成数组 [4,4,4]。\n最后将它们串联到一起 [2] + [4,4,4] = [2,4,4,4]。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,2,3]\n<strong>输出：</strong>[1,3,3]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 100</code></li>\n\t<li><code>nums.length % 2 == 0</code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<int> decompressRLElist(vector<int>& nums) {\n\n    }\n};",
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