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leetcode-problemset/leetcode-cn/originData/decode-xored-permutation.json

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{
"data": {
"question": {
"questionId": "1835",
"questionFrontendId": "1734",
"categoryTitle": "Algorithms",
"boundTopicId": 569630,
"title": "Decode XORed Permutation",
"titleSlug": "decode-xored-permutation",
"content": "<p>There is an integer array <code>perm</code> that is a permutation of the first <code>n</code> positive integers, where <code>n</code> is always <strong>odd</strong>.</p>\n\n<p>It was encoded into another integer array <code>encoded</code> of length <code>n - 1</code>, such that <code>encoded[i] = perm[i] XOR perm[i + 1]</code>. For example, if <code>perm = [1,3,2]</code>, then <code>encoded = [2,1]</code>.</p>\n\n<p>Given the <code>encoded</code> array, return <em>the original array</em> <code>perm</code>. It is guaranteed that the answer exists and is unique.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> encoded = [3,1]\n<strong>Output:</strong> [1,2,3]\n<strong>Explanation:</strong> If perm = [1,2,3], then encoded = [1 XOR 2,2 XOR 3] = [3,1]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> encoded = [6,5,4,6]\n<strong>Output:</strong> [2,4,1,5,3]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt;&nbsp;10<sup>5</sup></code></li>\n\t<li><code>n</code>&nbsp;is odd.</li>\n\t<li><code>encoded.length == n - 1</code></li>\n</ul>\n",
"translatedTitle": "解码异或后的排列",
"translatedContent": "<p>给你一个整数数组 <code>perm</code> ,它是前 <code>n</code> 个正整数的排列,且 <code>n</code> 是个 <strong>奇数</strong> 。</p>\n\n<p>它被加密成另一个长度为 <code>n - 1</code> 的整数数组 <code>encoded</code> ,满足 <code>encoded[i] = perm[i] XOR perm[i + 1]</code> 。比方说,如果 <code>perm = [1,3,2]</code> ,那么 <code>encoded = [2,1]</code> 。</p>\n\n<p>给你 <code>encoded</code> 数组,请你返回原始数组 <code>perm</code> 。题目保证答案存在且唯一。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><b>输入:</b>encoded = [3,1]\n<b>输出:</b>[1,2,3]\n<b>解释:</b>如果 perm = [1,2,3] ,那么 encoded = [1 XOR 2,2 XOR 3] = [3,1]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><b>输入:</b>encoded = [6,5,4,6]\n<b>输出:</b>[2,4,1,5,3]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt; 10<sup>5</sup></code></li>\n\t<li><code>n</code> 是奇数。</li>\n\t<li><code>encoded.length == n - 1</code></li>\n</ul>\n",
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"name": "Bit Manipulation",
"slug": "bit-manipulation",
"translatedName": "位运算",
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"code": "class Solution {\npublic:\n vector<int> decode(vector<int>& encoded) {\n\n }\n};",
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"hints": [
"Compute the XOR of the numbers between 1 and n, and think about how it can be used. Let it be x.",
"Think why n is odd.",
"perm[0] = x XOR encoded[1] XOR encoded[3] XOR encoded[5] ...",
"perm[i] = perm[i-1] XOR encoded[i-1]"
],
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