mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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188 lines
27 KiB
JSON
188 lines
27 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "1544",
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"questionFrontendId": "1448",
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"categoryTitle": "Algorithms",
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"boundTopicId": 247873,
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"title": "Count Good Nodes in Binary Tree",
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"titleSlug": "count-good-nodes-in-binary-tree",
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"content": "<p>Given a binary tree <code>root</code>, a node <em>X</em> in the tree is named <strong>good</strong> if in the path from root to <em>X</em> there are no nodes with a value <em>greater than</em> X.</p>\r\n\r\n<p>Return the number of <strong>good</strong> nodes in the binary tree.</p>\r\n\r\n<p> </p>\r\n<p><strong class=\"example\">Example 1:</strong></p>\r\n\r\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/04/02/test_sample_1.png\" style=\"width: 263px; height: 156px;\" /></strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> root = [3,1,4,3,null,1,5]\r\n<strong>Output:</strong> 4\r\n<strong>Explanation:</strong> Nodes in blue are <strong>good</strong>.\r\nRoot Node (3) is always a good node.\r\nNode 4 -> (3,4) is the maximum value in the path starting from the root.\r\nNode 5 -> (3,4,5) is the maximum value in the path\r\nNode 3 -> (3,1,3) is the maximum value in the path.</pre>\r\n\r\n<p><strong class=\"example\">Example 2:</strong></p>\r\n\r\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/04/02/test_sample_2.png\" style=\"width: 157px; height: 161px;\" /></strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> root = [3,3,null,4,2]\r\n<strong>Output:</strong> 3\r\n<strong>Explanation:</strong> Node 2 -> (3, 3, 2) is not good, because "3" is higher than it.</pre>\r\n\r\n<p><strong class=\"example\">Example 3:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> root = [1]\r\n<strong>Output:</strong> 1\r\n<strong>Explanation:</strong> Root is considered as <strong>good</strong>.</pre>\r\n\r\n<p> </p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li>The number of nodes in the binary tree is in the range <code>[1, 10^5]</code>.</li>\r\n\t<li>Each node's value is between <code>[-10^4, 10^4]</code>.</li>\r\n</ul>",
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"translatedTitle": "统计二叉树中好节点的数目",
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"translatedContent": "<p>给你一棵根为 <code>root</code> 的二叉树，请你返回二叉树中好节点的数目。</p>\n\n<p>「好节点」X 定义为：从根到该节点 X 所经过的节点中，没有任何节点的值大于 X 的值。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/05/16/test_sample_1.png\" style=\"height: 156px; width: 263px;\"></strong></p>\n\n<pre><strong>输入：</strong>root = [3,1,4,3,null,1,5]\n<strong>输出：</strong>4\n<strong>解释：</strong>图中蓝色节点为好节点。\n根节点 (3) 永远是个好节点。\n节点 4 -> (3,4) 是路径中的最大值。\n节点 5 -> (3,4,5) 是路径中的最大值。\n节点 3 -> (3,1,3) 是路径中的最大值。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/05/16/test_sample_2.png\" style=\"height: 161px; width: 157px;\"></strong></p>\n\n<pre><strong>输入：</strong>root = [3,3,null,4,2]\n<strong>输出：</strong>3\n<strong>解释：</strong>节点 2 -> (3, 3, 2) 不是好节点，因为 "3" 比它大。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>root = [1]\n<strong>输出：</strong>1\n<strong>解释：</strong>根节点是好节点。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>二叉树中节点数目范围是 <code>[1, 10^5]</code> 。</li>\n\t<li>每个节点权值的范围是 <code>[-10^4, 10^4]</code> 。</li>\n</ul>\n",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def goodNodes(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number}\n */\nvar goodNodes = function(root) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction goodNodes(root: TreeNode | null): number {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer\n */\n function goodNodes($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func goodNodes(_ root: TreeNode?) -> Int {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun goodNodes(root: TreeNode?): Int {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n int goodNodes(TreeNode? root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc goodNodes(root *TreeNode) int {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef good_nodes(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def goodNodes(root: TreeNode): Int = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn good_nodes(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {\n\n }\n}",
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"Use DFS (Depth First Search) to traverse the tree, and constantly keep track of the current path maximum."
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