leetcode-problemset/leetcode-cn/originData/compress-string-lcci.json

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            "questionId": "100161",
            "questionFrontendId": "面试题 01.06",
            "categoryTitle": "LCCI",
            "boundTopicId": 45552,
            "title": "Compress String LCCI",
            "titleSlug": "compress-string-lcci",
            "content": "<p>Implement a method to perform basic string compression using the counts of repeated characters. For example, the string aabcccccaaa would become a2blc5a3. If the &quot;compressed&quot; string would not become smaller than the original string, your method should return the original string. You can assume the string has only uppercase and lowercase letters (a - z).</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>&quot;aabcccccaaa&quot;\r\n<strong>Output: </strong>&quot;a2b1c5a3&quot;\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>&quot;abbccd&quot;\r\n<strong>Output: </strong>&quot;abbccd&quot;\r\n<strong>Explanation: </strong>\r\nThe compressed string is &quot;a1b2c2d1&quot;, which is longer than the original string.\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ol>\r\n\t<li><code>0 &lt;= S.length &lt;= 50000</code></li>\r\n</ol>\r\n",
            "translatedTitle": "字符串压缩",
            "translatedContent": "<p>字符串压缩。利用字符重复出现的次数，编写一种方法，实现基本的字符串压缩功能。比如，字符串<code>aabcccccaaa</code>会变为<code>a2b1c5a3</code>。若“压缩”后的字符串没有变短，则返回原先的字符串。你可以假设字符串中只包含大小写英文字母（a至z）。</p>\n\n<p> <strong>示例1:</strong></p>\n\n<pre>\n<strong> 输入</strong>：\"aabcccccaaa\"\n<strong> 输出</strong>：\"a2b1c5a3\"\n</pre>\n\n<p> <strong>示例2:</strong></p>\n\n<pre>\n<strong> 输入</strong>：\"abbccd\"\n<strong> 输出</strong>：\"abbccd\"\n<strong> 解释</strong>：\"abbccd\"压缩后为\"a1b2c2d1\"，比原字符串长度更长。\n</pre>\n\n<p><strong>提示：</strong></p>\n\n<ol>\n<li>字符串长度在[0, 50000]范围内。</li>\n</ol>\n",
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            "hints": [
                "先做容易的事。压缩字符串，然后再比较长度。",
                "注意不要把字符串重复连接在一起。这会非常低效。"
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