leetcode-problemset/leetcode-cn/originData/check-if-a-string-is-an-acronym-of-words.json

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        "question": {
            "questionId": "2977",
            "questionFrontendId": "2828",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2392179,
            "title": "Check if a String Is an Acronym of Words",
            "titleSlug": "check-if-a-string-is-an-acronym-of-words",
            "content": "<p>Given an array of strings <code>words</code> and a string <code>s</code>, determine if <code>s</code> is an <strong>acronym</strong> of words.</p>\n\n<p>The string <code>s</code> is considered an acronym of <code>words</code> if it can be formed by concatenating the <strong>first</strong> character of each string in <code>words</code> <strong>in order</strong>. For example, <code>&quot;ab&quot;</code> can be formed from <code>[&quot;apple&quot;, &quot;banana&quot;]</code>, but it can&#39;t be formed from <code>[&quot;bear&quot;, &quot;aardvark&quot;]</code>.</p>\n\n<p>Return <code>true</code><em> if </em><code>s</code><em> is an acronym of </em><code>words</code><em>, and </em><code>false</code><em> otherwise. </em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;alice&quot;,&quot;bob&quot;,&quot;charlie&quot;], s = &quot;abc&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> The first character in the words &quot;alice&quot;, &quot;bob&quot;, and &quot;charlie&quot; are &#39;a&#39;, &#39;b&#39;, and &#39;c&#39;, respectively. Hence, s = &quot;abc&quot; is the acronym. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;an&quot;,&quot;apple&quot;], s = &quot;a&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong> The first character in the words &quot;an&quot; and &quot;apple&quot; are &#39;a&#39; and &#39;a&#39;, respectively. \nThe acronym formed by concatenating these characters is &quot;aa&quot;. \nHence, s = &quot;a&quot; is not the acronym.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;never&quot;,&quot;gonna&quot;,&quot;give&quot;,&quot;up&quot;,&quot;on&quot;,&quot;you&quot;], s = &quot;ngguoy&quot;\n<strong>Output:</strong> true\n<strong>Explanation: </strong>By concatenating the first character of the words in the array, we get the string &quot;ngguoy&quot;. \nHence, s = &quot;ngguoy&quot; is the acronym.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>words[i]</code> and <code>s</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "判别首字母缩略词",
            "translatedContent": "<p>给你一个字符串数组&nbsp;<code>words</code> 和一个字符串 <code>s</code> ，请你判断 <code>s</code> 是不是 <code>words</code> 的 <strong>首字母缩略词</strong> 。</p>\n\n<p>如果可以按顺序串联 <code>words</code> 中每个字符串的第一个字符形成字符串 <code>s</code> ，则认为 <code>s</code> 是 <code>words</code> 的首字母缩略词。例如，<code>\"ab\"</code> 可以由 <code>[\"apple\", \"banana\"]</code> 形成，但是无法从 <code>[\"bear\", \"aardvark\"]</code> 形成。</p>\n\n<p>如果 <code>s</code> 是 <code>words</code> 的首字母缩略词，返回 <code>true</code><em> </em>；否则，返回<em> </em><code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"alice\",\"bob\",\"charlie\"], s = \"abc\"\n<strong>输出：</strong>true\n<strong>解释：</strong>words 中 \"alice\"、\"bob\" 和 \"charlie\" 的第一个字符分别是 'a'、'b' 和 'c'。因此，s = \"abc\" 是首字母缩略词。 \n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"an\",\"apple\"], s = \"a\"\n<strong>输出：</strong>false\n<strong>解释：</strong>words 中 \"an\" 和 \"apple\" 的第一个字符分别是 'a' 和 'a'。\n串联这些字符形成的首字母缩略词是 \"aa\" 。\n因此，s = \"a\" 不是首字母缩略词。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"never\",\"gonna\",\"give\",\"up\",\"on\",\"you\"], s = \"ngguoy\"\n<strong>输出：</strong>true\n<strong>解释：</strong>串联数组 words 中每个字符串的第一个字符，得到字符串 \"ngguoy\" 。\n因此，s = \"ngguoy\" 是首字母缩略词。 \n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>words[i]</code> 和 <code>s</code> 由小写英文字母组成</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    bool isAcronym(vector<string>& words, string s) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def isAcronym(self, words, s):\n        \"\"\"\n        :type words: List[str]\n        :type s: str\n        :rtype: bool\n        \"\"\"",
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                    "code": "/**\n * @param {string[]} words\n * @param {string} s\n * @return {boolean}\n */\nvar isAcronym = function(words, s) {\n\n};",
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                    "code": "# @param {String[]} words\n# @param {String} s\n# @return {Boolean}\ndef is_acronym(words, s)\n\nend",
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                    "code": "object Solution {\n    def isAcronym(words: List[String], s: String): Boolean = {\n\n    }\n}",
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                "<div class=\"_1l1MA\">Concatenate the first characters of the strings in <code>words</code>, and compare the resulting concatenation to <code>s</code>.</div>"
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