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{
"data": {
"question": {
"questionId": "401",
"questionFrontendId": "401",
"categoryTitle": "Algorithms",
"boundTopicId": 1625,
"title": "Binary Watch",
"titleSlug": "binary-watch",
"content": "<p>A binary watch has 4 LEDs on the top to represent the hours (0-11), and 6 LEDs on the bottom to represent&nbsp;the minutes (0-59). Each LED represents a zero or one, with the least significant bit on the right.</p>\n\n<ul>\n\t<li>For example, the below binary watch reads <code>&quot;4:51&quot;</code>.</li>\n</ul>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/08/binarywatch.jpg\" style=\"width: 500px; height: 500px;\" /></p>\n\n<p>Given an integer <code>turnedOn</code> which represents the number of LEDs that are currently on (ignoring the PM), return <em>all possible times the watch could represent</em>. You may return the answer in <strong>any order</strong>.</p>\n\n<p>The hour must not contain a leading zero.</p>\n\n<ul>\n\t<li>For example, <code>&quot;01:00&quot;</code> is not valid. It should be <code>&quot;1:00&quot;</code>.</li>\n</ul>\n\n<p>The minute must&nbsp;consist of two digits and may contain a leading zero.</p>\n\n<ul>\n\t<li>For example, <code>&quot;10:2&quot;</code> is not valid. It should be <code>&quot;10:02&quot;</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> turnedOn = 1\n<strong>Output:</strong> [\"0:01\",\"0:02\",\"0:04\",\"0:08\",\"0:16\",\"0:32\",\"1:00\",\"2:00\",\"4:00\",\"8:00\"]\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> turnedOn = 9\n<strong>Output:</strong> []\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= turnedOn &lt;= 10</code></li>\n</ul>\n",
"translatedTitle": "二进制手表",
"translatedContent": "<p>二进制手表顶部有 4 个 LED 代表<strong> 小时0-11</strong>,底部的 6 个 LED 代表<strong> 分钟0-59</strong>。每个 LED 代表一个 0 或 1最低位在右侧。</p>\n\n<ul>\n\t<li>例如,下面的二进制手表读取 <code>\"4:51\"</code> 。</li>\n</ul>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/04/08/binarywatch.jpg\" style=\"height: 300px; width\" /></p>\n\n<p>给你一个整数 <code>turnedOn</code> ,表示当前亮着的 LED 的数量,返回二进制手表可以表示的所有可能时间。你可以 <strong>按任意顺序</strong> 返回答案。</p>\n\n<p>小时不会以零开头:</p>\n\n<ul>\n\t<li>例如,<code>\"01:00\"</code> 是无效的时间,正确的写法应该是 <code>\"1:00\"</code> 。</li>\n</ul>\n\n<p>分钟必须由两位数组成,可能会以零开头:</p>\n\n<ul>\n\t<li>例如,<code>\"10:2\"</code> 是无效的时间,正确的写法应该是 <code>\"10:02\"</code> 。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>turnedOn = 1\n<strong>输出:</strong>[\"0:01\",\"0:02\",\"0:04\",\"0:08\",\"0:16\",\"0:32\",\"1:00\",\"2:00\",\"4:00\",\"8:00\"]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>turnedOn = 9\n<strong>输出:</strong>[]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= turnedOn &lt;= 10</code></li>\n</ul>\n",
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"topicTags": [
{
"name": "Bit Manipulation",
"slug": "bit-manipulation",
"translatedName": "位运算",
"__typename": "TopicTagNode"
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"code": "class Solution {\npublic:\n vector<string> readBinaryWatch(int turnedOn) {\n\n }\n};",
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"code": "class Solution {\n public List<String> readBinaryWatch(int turnedOn) {\n\n }\n}",
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"code": "class Solution(object):\n def readBinaryWatch(self, turnedOn):\n \"\"\"\n :type turnedOn: int\n :rtype: List[str]\n \"\"\"",
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"code": "class Solution:\n def readBinaryWatch(self, turnedOn: int) -> List[str]:",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar ** readBinaryWatch(int turnedOn, int* returnSize){\n\n}",
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"code": "public class Solution {\n public IList<string> ReadBinaryWatch(int turnedOn) {\n\n }\n}",
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"code": "/**\n * @param {number} turnedOn\n * @return {string[]}\n */\nvar readBinaryWatch = function(turnedOn) {\n\n};",
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"code": "class Solution {\n fun readBinaryWatch(turnedOn: Int): List<String> {\n\n }\n}",
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"code": "class Solution {\n List<String> readBinaryWatch(int turnedOn) {\n\n }\n}",
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"code": "# @param {Integer} turned_on\n# @return {String[]}\ndef read_binary_watch(turned_on)\n\nend",
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"code": "object Solution {\n def readBinaryWatch(turnedOn: Int): List[String] = {\n\n }\n}",
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"lang": "Rust",
"langSlug": "rust",
"code": "impl Solution {\n pub fn read_binary_watch(turned_on: i32) -> Vec<String> {\n\n }\n}",
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"hints": [
"Simplify by seeking for solutions that involve comparing bit counts.",
"Consider calculating all possible times for comparison purposes."
],
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