mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
186 lines
27 KiB
JSON
186 lines
27 KiB
JSON
{
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"question": {
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"questionId": "144",
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"questionFrontendId": "144",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1452,
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"title": "Binary Tree Preorder Traversal",
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"titleSlug": "binary-tree-preorder-traversal",
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"content": "<p>Given the <code>root</code> of a binary tree, return <em>the preorder traversal of its nodes' values</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg\" style=\"width: 125px; height: 200px;\" />\n<pre>\n<strong>Input:</strong> root = [1,null,2,3]\n<strong>Output:</strong> [1,2,3]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = []\n<strong>Output:</strong> []\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [1]\n<strong>Output:</strong> [1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[0, 100]</code>.</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n</ul>\n\n<p> </p>\n<p><strong>Follow up:</strong> Recursive solution is trivial, could you do it iteratively?</p>\n",
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"translatedTitle": "二叉树的前序遍历",
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"translatedContent": "<p>给你二叉树的根节点 <code>root</code> ，返回它节点值的 <strong>前序</strong><em> </em>遍历。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg\" style=\"width: 202px; height: 324px;\" />\n<pre>\n<strong>输入：</strong>root = [1,null,2,3]\n<strong>输出：</strong>[1,2,3]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = []\n<strong>输出：</strong>[]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [1]\n<strong>输出：</strong>[1]\n</pre>\n\n<p><strong>示例 4：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/inorder_5.jpg\" style=\"width: 202px; height: 202px;\" />\n<pre>\n<strong>输入：</strong>root = [1,2]\n<strong>输出：</strong>[1,2]\n</pre>\n\n<p><strong>示例 5：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/15/inorder_4.jpg\" style=\"width: 202px; height: 202px;\" />\n<pre>\n<strong>输入：</strong>root = [1,null,2]\n<strong>输出：</strong>[1,2]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目在范围 <code>[0, 100]</code> 内</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>递归算法很简单，你可以通过迭代算法完成吗？</p>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n vector<int> preorderTraversal(TreeNode* root) {\n\n }\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def preorderTraversal(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: List[int]\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public IList<int> PreorderTraversal(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number[]}\n */\nvar preorderTraversal = function(root) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction preorderTraversal(root: TreeNode | null): number[] {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer[]\n */\n function preorderTraversal($root) {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun preorderTraversal(root: TreeNode?): List<Int> {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer[]}\ndef preorder_traversal(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def preorderTraversal(root: TreeNode): List[Int] = {\n\n }\n}",
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