leetcode-problemset/leetcode-cn/originData/best-time-to-buy-and-sell-stock-ii.json

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            "title": "Best Time to Buy and Sell Stock II",
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            "content": "<p>You are given an integer array <code>prices</code> where <code>prices[i]</code> is the price of a given stock on the <code>i<sup>th</sup></code> day.</p>\n\n<p>On each day, you may decide to buy and/or sell the stock. You can only hold <strong>at most one</strong> share of the stock at any time. However, you can buy it then immediately sell it on the <strong>same day</strong>.</p>\n\n<p>Find and return <em>the <strong>maximum</strong> profit you can achieve</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [7,1,5,3,6,4]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.\nThen buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.\nTotal profit is 4 + 3 = 7.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [1,2,3,4,5]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.\nTotal profit is 4.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> prices = [7,6,4,3,1]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There is no way to make a positive profit, so we never buy the stock to achieve the maximum profit of 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= prices.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= prices[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "买卖股票的最佳时机 II",
            "translatedContent": "<p>给你一个整数数组 <code>prices</code> ，其中&nbsp;<code>prices[i]</code> 表示某支股票第 <code>i</code> 天的价格。</p>\n\n<p>在每一天，你可以决定是否购买和/或出售股票。你在任何时候&nbsp;<strong>最多</strong>&nbsp;只能持有 <strong>一股</strong> 股票。你也可以先购买，然后在 <strong>同一天</strong> 出售。</p>\n\n<p>返回 <em>你能获得的 <strong>最大</strong> 利润</em>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [7,1,5,3,6,4]\n<strong>输出：</strong>7\n<strong>解释：</strong>在第 2 天（股票价格 = 1）的时候买入，在第 3 天（股票价格 = 5）的时候卖出, 这笔交易所能获得利润 = 5 - 1 = 4 。\n&nbsp;    随后，在第 4 天（股票价格 = 3）的时候买入，在第 5 天（股票价格 = 6）的时候卖出, 这笔交易所能获得利润 = 6 - 3 = 3 。\n     总利润为 4 + 3 = 7 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [1,2,3,4,5]\n<strong>输出：</strong>4\n<strong>解释：</strong>在第 1 天（股票价格 = 1）的时候买入，在第 5 天 （股票价格 = 5）的时候卖出, 这笔交易所能获得利润 = 5 - 1 = 4 。\n&nbsp;    总利润为 4 。</pre>\n\n<p><strong>示例&nbsp;3：</strong></p>\n\n<pre>\n<strong>输入：</strong>prices = [7,6,4,3,1]\n<strong>输出：</strong>0\n<strong>解释：</strong>在这种情况下, 交易无法获得正利润，所以不参与交易可以获得最大利润，最大利润为 0 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= prices.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= prices[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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