leetcode-problemset/leetcode-cn/originData/apply-transform-over-each-element-in-array.json

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        "question": {
            "questionId": "2747",
            "questionFrontendId": "2635",
            "categoryTitle": "JavaScript",
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            "title": "Apply Transform Over Each Element in Array",
            "titleSlug": "apply-transform-over-each-element-in-array",
            "content": "<p>Given an integer array&nbsp;<code>arr</code>&nbsp;and a mapping function&nbsp;<code>fn</code>, return&nbsp;a new array with a transformation applied to each element.</p>\n\n<p>The returned array should be created such that&nbsp;<code>returnedArray[i] = fn(arr[i], i)</code>.</p>\n\n<p>Please solve it without the built-in <code>Array.map</code> method.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,2,3], fn = function plusone(n) { return n + 1; }\n<strong>Output:</strong> [2,3,4]\n<strong>Explanation:</strong>\nconst newArray = map(arr, plusone); // [2,3,4]\nThe function increases each value in the array by one. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,2,3], fn = function plusI(n, i) { return n + i; }\n<strong>Output:</strong> [1,3,5]\n<strong>Explanation:</strong> The function increases each value by the index it resides in.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [10,20,30], fn = function constant() { return 42; }\n<strong>Output:</strong> [42,42,42]\n<strong>Explanation:</strong> The function always returns 42.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= arr.length &lt;= 1000</code></li>\n\t<li><code><font face=\"monospace\">-10<sup>9</sup>&nbsp;&lt;= arr[i] &lt;= 10<sup>9</sup></font></code></li>\n\t<li><code>fn</code> returns a number</li>\n</ul>\n",
            "translatedTitle": "转换数组中的每个元素",
            "translatedContent": "<p>编写一个函数，这个函数接收一个整数数组&nbsp;<code>arr</code> 和一个映射函数&nbsp; <code>fn</code>&nbsp;，通过该映射函数返回一个新的数组。</p>\n\n<p>返回数组的创建语句应为 <code>returnedArray[i] = fn(arr[i], i)</code>&nbsp;。</p>\n\n<p>请你在不使用内置方法&nbsp;<code>Array.map</code>&nbsp;的前提下解决这个问题。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [1,2,3], fn = function plusone(n) { return n + 1; }\n<strong>输出：</strong>[2,3,4]\n<strong>解释： </strong>\nconst newArray = map(arr, plusone); // [2,3,4]\n此映射函数返回值是将数组中每个元素的值加 1。\n</pre>\n\n<p><strong class=\"example\">示例</strong><strong class=\"example\"> 2:</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [1,2,3], fn = function plusI(n, i) { return n + i; }\n<strong>输出：</strong>[1,3,5]\n<strong>解释：</strong>此映射函数返回值根据输入数组索引增加每个值。\n</pre>\n\n<p><strong class=\"example\">示例&nbsp;3:</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [10,20,30], fn = function constant() { return 42; }\n<strong>输出：</strong>[42,42,42]\n<strong>解释：</strong>此映射函数返回值恒为 42。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= arr.length &lt;= 1000</code></li>\n\t<li><code><font face=\"monospace\">-10<sup>9</sup>&nbsp;&lt;= arr[i] &lt;= 10<sup>9</sup></font></code></li>\n\t<li><font face=\"monospace\"><code>fn</code> 返回一个数</font></li>\n</ul>\n<span style=\"display:block\"><span style=\"height:0px\"><span style=\"position:absolute\">​​​​​​</span></span></span>",
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                    "code": "/**\n * @param {number[]} arr\n * @param {Function} fn\n * @return {number[]}\n */\nvar map = function(arr, fn) {\n    \n};",
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            "hints": [
                "Start by creating an array that will eventually be returned.",
                "Loop over each element in the passed array. Push fn(arr[i]) to the returned array."
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            "sampleTestCase": "function plusone(n) { return n + 1; }\n[1,2,3]",
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