mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
187 lines
23 KiB
JSON
187 lines
23 KiB
JSON
{
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"questionId": "1000373",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1016616,
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"title": "志愿者调配",
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"titleSlug": "05ZEDJ",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "志愿者调配",
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"translatedContent": "「力扣挑战赛」有 `n` 个比赛场馆（场馆编号从 `0` 开始），场馆之间的通道分布情况记录于二维数组 `edges` 中，`edges[i]= [x, y]` 表示第 `i` 条通道连接场馆 `x` 和场馆 `y`(即两个场馆相邻)。初始每个场馆中都有一定人数的志愿者（不同场馆人数可能不同），后续 `m` 天每天均会根据赛事热度进行志愿者人数调配。调配方案分为如下三种：\n1. 将编号为 `idx` 的场馆内的志愿者人数减半；\n2. 将编号为 `idx` 的场馆相邻的场馆的志愿者人数都加上编号为 `idx` 的场馆的志愿者人数；\n3. 将编号为 `idx` 的场馆相邻的场馆的志愿者人数都减去编号为 `idx` 的场馆的志愿者人数。\n\n所有的调配信息记录于数组 `plans` 中，`plans[i] = [num,idx]` 表示第 `i` 天对编号 `idx` 的场馆执行了第 `num` 种调配方案。\n在比赛结束后对调配方案进行复盘时，不慎将第 `0` 个场馆的**最终**志愿者人数丢失，只保留了**初始**所有场馆的志愿者总人数 `totalNum` ，以及记录了第 `1 ~ n-1` 个场馆的**最终**志愿者人数的一维数组 `finalCnt`。请你根据现有的信息求出初始每个场馆的志愿者人数，并按场馆编号顺序返回志愿者人数列表。\n\n**注意：**\n- 测试数据保证当某场馆进行第一种调配时，该场馆的志愿者人数一定为偶数；\n- 测试数据保证当某场馆进行第三种调配时，该场馆的相邻场馆志愿者人数不为负数；\n- 测试数据保证比赛开始时每个场馆的志愿者人数都不超过 `10^9`；\n- 测试数据保证给定的场馆间的道路分布情况中不会出现自环、重边的情况。\n\n\n**示例 1：**\n>\n> 输入：\n>`finalCnt = [1,16], totalNum = 21, edges = [[0,1],[1,2]], plans = [[2,1],[1,0],[3,0]]`\n>\n> 输出：`[5,7,9]`\n>\n> 解释：\n> {:height=200}\n\n\n**示例 2 ：**\n> 输入：\n>`finalCnt = [4,13,4,3,8], totalNum = 54, edges = [[0,3],[1,3],[4,3],[2,3],[2,5]], plans = [[1,1],[3,3],[2,5],[1,0]]`\n>\n> 输出：`[10,16,9,4,7,8]`\n\n\n\n**提示：**\n- `2 <= n <= 5*10^4`\n- `1 <= edges.length <= min((n * (n - 1)) / 2, 5*10^4)`\n- `0 <= edges[i][0], edges[i][1] < n`\n- `1 <= plans.length <= 10`\n- `1 <= plans[i][0] <=3`\n- `0 <= plans[i][1] < n`\n- `finalCnt.length = n-1`\n- `0 <= finalCnt[i] < 10^9`\n- `0 <= totalNum < 5*10^13`\n",
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