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leetcode-problemset/leetcode-cn/problem (English)/只出现一次的数字(English) [single-number].html
2025-09-29 14:43:44 +08:00

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<p>Given a <strong>non-empty</strong>&nbsp;array of integers <code>nums</code>, every element appears <em>twice</em> except for one. Find that single one.</p>
<p>You must&nbsp;implement a solution with a linear runtime complexity and use&nbsp;only constant&nbsp;extra space.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [2,2,1]</span></p>
<p><strong>Output:</strong> <span class="example-io">1</span></p>
</div>
<p><strong class="example">Example 2:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [4,1,2,1,2]</span></p>
<p><strong>Output:</strong> <span class="example-io">4</span></p>
</div>
<p><strong class="example">Example 3:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1]</span></p>
<p><strong>Output:</strong> <span class="example-io">1</span></p>
</div>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>
<li><code>-3 * 10<sup>4</sup> &lt;= nums[i] &lt;= 3 * 10<sup>4</sup></code></li>
<li>Each element in the array appears twice except for one element which appears only once.</li>
</ul>