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leetcode-problemset/leetcode-cn/problem (English)/前 K 个高频元素(English) [top-k-frequent-elements].html
2025-09-29 14:43:44 +08:00

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<p>Given an integer array <code>nums</code> and an integer <code>k</code>, return <em>the</em> <code>k</code> <em>most frequent elements</em>. You may return the answer in <strong>any order</strong>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,1,1,2,2,3], k = 2</span></p>
<p><strong>Output:</strong> <span class="example-io">[1,2]</span></p>
</div>
<p><strong class="example">Example 2:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1], k = 1</span></p>
<p><strong>Output:</strong> <span class="example-io">[1]</span></p>
</div>
<p><strong class="example">Example 3:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,1,2,1,2,3,1,3,2], k = 2</span></p>
<p><strong>Output:</strong> <span class="example-io">[1,2]</span></p>
</div>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
<li><code>k</code> is in the range <code>[1, the number of unique elements in the array]</code>.</li>
<li>It is <strong>guaranteed</strong> that the answer is <strong>unique</strong>.</li>
</ul>
<p>&nbsp;</p>
<p><strong>Follow up:</strong> Your algorithm&#39;s time complexity must be better than <code>O(n log n)</code>, where n is the array&#39;s size.</p>