mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-10-20 20:46:47 +08:00
192 lines
22 KiB
JSON
192 lines
22 KiB
JSON
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"categoryTitle": "Algorithms",
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"title": "Transpose Matrix",
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"content": "<p>Given a 2D integer array <code>matrix</code>, return <em>the <strong>transpose</strong> of</em> <code>matrix</code>.</p>\n\n<p>The <strong>transpose</strong> of a matrix is the matrix flipped over its main diagonal, switching the matrix's row and column indices.</p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/10/hint_transpose.png\" style=\"width: 600px; height: 197px;\" /></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> matrix = [[1,2,3],[4,5,6],[7,8,9]]\n<strong>Output:</strong> [[1,4,7],[2,5,8],[3,6,9]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> matrix = [[1,2,3],[4,5,6]]\n<strong>Output:</strong> [[1,4],[2,5],[3,6]]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 1000</code></li>\n\t<li><code>1 <= m * n <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= matrix[i][j] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "转置矩阵",
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"translatedContent": "<p>给你一个二维整数数组 <code>matrix</code>， 返回 <code>matrix</code> 的 <strong>转置矩阵</strong> 。</p>\n\n<p>矩阵的 <strong>转置</strong> 是指将矩阵的主对角线翻转，交换矩阵的行索引与列索引。</p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/10/hint_transpose.png\" style=\"width: 600px; height: 197px;\" /></p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>matrix = [[1,2,3],[4,5,6],[7,8,9]]\n<strong>输出：</strong>[[1,4,7],[2,5,8],[3,6,9]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>matrix = [[1,2,3],[4,5,6]]\n<strong>输出：</strong>[[1,4],[2,5],[3,6]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 1000</code></li>\n\t<li><code>1 <= m * n <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= matrix[i][j] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"We don't need any special algorithms to do this. You just need to know what the transpose of a matrix looks like. Rows become columns and vice versa!"
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