leetcode-problemset/leetcode-cn/originData/t3fKg1.json

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        "question": {
            "questionId": "1000219",
            "questionFrontendId": "LCP 32",
            "categoryTitle": "Algorithms",
            "boundTopicId": 701752,
            "title": "批量处理任务",
            "titleSlug": "t3fKg1",
            "content": "English description is not available for the problem. Please switch to Chinese.",
            "translatedTitle": "批量处理任务",
            "translatedContent": "某实验室计算机待处理任务以 `[start,end,period]` 格式记于二维数组 `tasks`，表示完成该任务的时间范围为起始时间 `start` 至结束时间 `end` 之间，需要计算机投入 `period` 的时长，注意：\n1. `period` 可为不连续时间\n2. 首尾时间均包含在内\n\n处于开机状态的计算机可同时处理任意多个任务，请返回电脑最少开机多久，可处理完所有任务。\n\n**示例 1：**\n>输入：`tasks = [[1,3,2],[2,5,3],[5,6,2]]`\n>\n>输出：`4`\n>\n>解释：\n>tasks[0] 选择时间点 2、3；\n>tasks[1] 选择时间点 2、3、5；\n>tasks[2] 选择时间点 5、6；\n>因此计算机仅需在时间点 2、3、5、6 四个时刻保持开机即可完成任务。\n\n**示例 2：**\n>输入：`tasks = [[2,3,1],[5,5,1],[5,6,2]]`\n>\n>输出：`3`\n>\n>解释：\n>tasks[0] 选择时间点 2 或 3；\n>tasks[1] 选择时间点 5；\n>tasks[2] 选择时间点 5、6；\n>因此计算机仅需在时间点 2、5、6 或 3、5、6 三个时刻保持开机即可完成任务。\n\n**提示：**\n- `2 <= tasks.length <= 10^5`\n- `tasks[i].length == 3`\n- `0 <= tasks[i][0] <= tasks[i][1] <= 10^9`\n- `1 <= tasks[i][2] <= tasks[i][1]-tasks[i][0] + 1`",
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                    "name": "Greedy",
                    "slug": "greedy",
                    "translatedName": "贪心",
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                {
                    "name": "Array",
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            "exampleTestcases": "[[1,3,2],[2,5,3],[5,6,2]]\n[[2,3,1],[5,5,1],[5,6,2]]",
            "__typename": "QuestionNode"
        }
    }
}