leetcode-problemset/leetcode-cn/originData/number-of-distinct-averages.json

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            "title": "Number of Distinct Averages",
            "titleSlug": "number-of-distinct-averages",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of <strong>even</strong> length.</p>\n\n<p>As long as <code>nums</code> is <strong>not</strong> empty, you must repetitively:</p>\n\n<ul>\n\t<li>Find the minimum number in <code>nums</code> and remove it.</li>\n\t<li>Find the maximum number in <code>nums</code> and remove it.</li>\n\t<li>Calculate the average of the two removed numbers.</li>\n</ul>\n\n<p>The <strong>average</strong> of two numbers <code>a</code> and <code>b</code> is <code>(a + b) / 2</code>.</p>\n\n<ul>\n\t<li>For example, the average of <code>2</code> and <code>3</code> is <code>(2 + 3) / 2 = 2.5</code>.</li>\n</ul>\n\n<p>Return<em> the number of <strong>distinct</strong> averages calculated using the above process</em>.</p>\n\n<p><strong>Note</strong> that when there is a tie for a minimum or maximum number, any can be removed.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,1,4,0,3,5]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\n1. Remove 0 and 5, and the average is (0 + 5) / 2 = 2.5. Now, nums = [4,1,4,3].\n2. Remove 1 and 4. The average is (1 + 4) / 2 = 2.5, and nums = [4,3].\n3. Remove 3 and 4, and the average is (3 + 4) / 2 = 3.5.\nSince there are 2 distinct numbers among 2.5, 2.5, and 3.5, we return 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,100]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nThere is only one average to be calculated after removing 1 and 100, so we return 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>nums.length</code> is even.</li>\n\t<li><code>0 &lt;= nums[i] &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "不同的平均值数目",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <strong>偶数</strong>&nbsp;的整数数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p>只要&nbsp;<code>nums</code> <strong>不是</strong>&nbsp;空数组，你就重复执行以下步骤：</p>\n\n<ul>\n\t<li>找到&nbsp;<code>nums</code>&nbsp;中的最小值，并删除它。</li>\n\t<li>找到&nbsp;<code>nums</code>&nbsp;中的最大值，并删除它。</li>\n\t<li>计算删除两数的平均值。</li>\n</ul>\n\n<p>两数 <code>a</code>&nbsp;和 <code>b</code>&nbsp;的 <strong>平均值</strong>&nbsp;为&nbsp;<code>(a + b) / 2</code>&nbsp;。</p>\n\n<ul>\n\t<li>比方说，<code>2</code>&nbsp;和&nbsp;<code>3</code>&nbsp;的平均值是&nbsp;<code>(2 + 3) / 2 = 2.5</code>&nbsp;。</li>\n</ul>\n\n<p>返回上述过程能得到的 <strong>不同</strong>&nbsp;平均值的数目。</p>\n\n<p><strong>注意</strong>&nbsp;，如果最小值或者最大值有重复元素，可以删除任意一个。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [4,1,4,0,3,5]\n<b>输出：</b>2\n<strong>解释：</strong>\n1. 删除 0 和 5 ，平均值是 (0 + 5) / 2 = 2.5 ，现在 nums = [4,1,4,3] 。\n2. 删除 1 和 4 ，平均值是 (1 + 4) / 2 = 2.5 ，现在 nums = [4,3] 。\n3. 删除 3 和 4 ，平均值是 (3 + 4) / 2 = 3.5 。\n2.5 ，2.5 和 3.5 之中总共有 2 个不同的数，我们返回 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,100]\n<b>输出：</b>1\n<strong>解释：</strong>\n删除 1 和 100 后只有一个平均值，所以我们返回 1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>nums.length</code>&nbsp;是偶数。</li>\n\t<li><code>0 &lt;= nums[i] &lt;= 100</code></li>\n</ul>\n",
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