leetcode-problemset/leetcode-cn/originData/minimum-reverse-operations.json

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        "question": {
            "questionId": "2726",
            "questionFrontendId": "2612",
            "categoryTitle": "Algorithms",
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            "title": "Minimum Reverse Operations",
            "titleSlug": "minimum-reverse-operations",
            "content": "<p>You are given an integer <code>n</code> and an integer <code>p</code> representing an array <code>arr</code> of length <code>n</code> where all elements are set to 0&#39;s, except position <code>p</code> which is set to 1. You are also given an integer array <code>banned</code> containing restricted positions. Perform the following operation on <code>arr</code>:</p>\n\n<ul>\n\t<li>Reverse a <span data-keyword=\"subarray-nonempty\"><strong>subarray</strong></span> with size <code>k</code> if the single 1 is not set to a position in <code>banned</code>.</li>\n</ul>\n\n<p>Return an integer array <code>answer</code> with <code>n</code> results where the <code>i<sup>th</sup></code> result is<em> </em>the <strong>minimum</strong> number of operations needed to bring the single 1 to position <code>i</code> in <code>arr</code>, or -1 if it is impossible.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 4, p = 0, banned = [1,2], k = 4</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[0,-1,-1,1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Initially 1 is placed at position 0 so the number of operations we need for position 0 is 0.</li>\n\t<li>We can never place 1 on the banned positions, so the answer for positions 1 and 2 is -1.</li>\n\t<li>Perform the operation of size 4 to reverse the whole array.</li>\n\t<li>After a single operation 1 is at position 3 so the answer for position 3 is 1.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 5, p = 0, banned = [2,4], k = 3</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[0,-1,-1,-1,-1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Initially 1 is placed at position 0 so the number of operations we need for position 0 is 0.</li>\n\t<li>We cannot perform the operation on the subarray positions <code>[0, 2]</code> because position 2 is in banned.</li>\n\t<li>Because 1 cannot be set at position 2, it is impossible to set 1 at other positions in more operations.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 4, p = 2, banned = [0,1,3], k = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[-1,-1,0,-1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Perform operations of size 1 and 1 never changes its position.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= p &lt;= n - 1</code></li>\n\t<li><code>0 &lt;= banned.length &lt;= n - 1</code></li>\n\t<li><code>0 &lt;= banned[i] &lt;= n - 1</code></li>\n\t<li><code>1 &lt;= k &lt;= n&nbsp;</code></li>\n\t<li><code>banned[i] != p</code></li>\n\t<li>all values in <code>banned</code>&nbsp;are <strong>unique</strong>&nbsp;</li>\n</ul>\n",
            "translatedTitle": "最少翻转操作数",
            "translatedContent": "<p>给定一个整数&nbsp;<code>n</code>&nbsp;和一个整数&nbsp;<code>p</code>，它们表示一个长度为 <code>n</code> 且除了下标为&nbsp;<code>p</code>&nbsp;处是 <code>1</code>&nbsp;以外，其他所有数都是 <code>0</code>&nbsp;的数组&nbsp;<code>arr</code>。同时给定一个整数数组&nbsp;<code>banned</code>&nbsp;，它包含数组中的一些限制位置。在&nbsp;<code>arr</code>&nbsp;上进行下列操作：</p>\n\n<ul>\n\t<li>如果单个 1 不在&nbsp;<code>banned</code>&nbsp;中的位置上，反转大小为 <code>k</code> 的 <strong><span data-keyword=\"subarray-nonempty\">子数组</span></strong>。</li>\n</ul>\n\n<p>返回一个包含&nbsp;<code>n</code>&nbsp;个结果的整数数组&nbsp;<code>answer</code>，其中第&nbsp;<code>i</code>&nbsp;个结果是将&nbsp;<code>1</code>&nbsp;放到位置&nbsp;<code>i</code>&nbsp;处所需的&nbsp;<strong>最少</strong>&nbsp;翻转操作次数，如果无法放到位置&nbsp;<code>i</code>&nbsp;处，此数为&nbsp;<code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>n = 4, p = 0, banned = [1,2], k = 4</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[0,-1,-1,1]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>一开始 1 位于位置 0，因此我们需要在位置 0 上的操作数是 0。</li>\n\t<li>我们不能将 1 放置在被禁止的位置上，所以位置 1 和 2 的答案是 -1。</li>\n\t<li>执行大小为 4 的操作以反转整个数组。</li>\n\t<li>在一次操作后，1 位于位置 3，因此位置 3 的答案是 1。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>n = 5, p = 0, banned = [2,4], k = 3</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[0,-1,-1,-1,-1]</span></p>\n\n<p><b>解释：</b></p>\n\n<ul>\n\t<li>一开始 1 位于位置 0，因此我们需要在位置 0 上的操作数是 0。</li>\n\t<li>我们不能在&nbsp;<code>[0, 2]</code>&nbsp;的子数组位置上执行操作，因为位置 2 在 banned 中。</li>\n\t<li>由于 1 不能够放置在位置 2 上，使用更多操作将 1 放置在其它位置上是不可能的。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>n = 4, p = 2, banned = [0,1,3], k = 1</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[-1,-1,0,-1]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>执行大小为 1 的操作，且 1 永远不会改变位置。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= p &lt;= n - 1</code></li>\n\t<li><code>0 &lt;= banned.length &lt;= n - 1</code></li>\n\t<li><code>0 &lt;= banned[i] &lt;= n - 1</code></li>\n\t<li><code>1 &lt;= k &lt;= n&nbsp;</code></li>\n\t<li><code>banned[i] != p</code></li>\n\t<li><code>banned</code>&nbsp;中的值 <strong>互不相同</strong>&nbsp;。</li>\n</ul>\n",
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