leetcode-problemset/leetcode-cn/originData/minimum-operations-to-equalize-array.json

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        "question": {
            "questionId": "3998",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Operations to Equalize Array",
            "titleSlug": "minimum-operations-to-equalize-array",
            "content": "<p>You are given an integer array <code>nums</code> of length <code>n</code>.</p>\n\n<p>In one operation, choose any subarray <code>nums[l...r]</code> (<code>0 &lt;= l &lt;= r &lt; n</code>) and <strong>replace</strong> each element in that subarray with the <strong>bitwise AND</strong> of all elements.</p>\n\n<p>Return the <strong>minimum</strong> number of operations required to make all elements of <code>nums</code> equal.</p>\nA <strong>subarray</strong> is a contiguous <b>non-empty</b> sequence of elements within an array.\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Choose <code>nums[0...1]</code>: <code>(1 AND 2) = 0</code>, so the array becomes <code>[0, 0]</code> and all elements are equal in 1 operation.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [5,5,5]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><code>nums</code> is <code>[5, 5, 5]</code> which already has all elements equal, so 0 operations are required.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "数组元素相等的最小操作次数",
            "translatedContent": "<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code>。</p>\n\n<p>在一次操作中，可以选择任意子数组 <code>nums[l...r]</code> （<code>0 &lt;= l &lt;= r &lt; n</code>），并将该子数组中的每个元素&nbsp;<strong>替换&nbsp;</strong>为所有元素的&nbsp;<strong>按位与（bitwise AND）</strong>结果。</p>\n\n<p>返回使数组 <code>nums</code> 中所有元素相等所需的最小操作次数。</p>\n\n<p><strong>子数组&nbsp;</strong>是数组中连续的、非空的元素序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [1,2]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>选择 <code>nums[0...1]</code>：<code>(1 AND 2) = 0</code>，因此数组变为 <code>[0, 0]</code>，所有元素在一次操作后相等。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [5,5,5]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p><code>nums</code> 本身是 <code>[5, 5, 5]</code>，所有元素已经相等，因此不需要任何操作。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                "If all elements of <code>nums</code> are already equal, how many operations are needed?",
                "The answer is either <code>0</code> or <code>1</code>.",
                "The answer is <code>0</code> if all values in the array are initially equal, and <code>1</code> otherwise, since you can apply the AND operation on the whole array in one step."
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