leetcode-problemset/leetcode-cn/originData/minimum-ascii-delete-sum-for-two-strings.json

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            "title": "Minimum ASCII Delete Sum for Two Strings",
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            "content": "<p>Given two strings <code>s1</code> and&nbsp;<code>s2</code>, return <em>the lowest <strong>ASCII</strong> sum of deleted characters to make two strings equal</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;sea&quot;, s2 = &quot;eat&quot;\n<strong>Output:</strong> 231\n<strong>Explanation:</strong> Deleting &quot;s&quot; from &quot;sea&quot; adds the ASCII value of &quot;s&quot; (115) to the sum.\nDeleting &quot;t&quot; from &quot;eat&quot; adds 116 to the sum.\nAt the end, both strings are equal, and 115 + 116 = 231 is the minimum sum possible to achieve this.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;delete&quot;, s2 = &quot;leet&quot;\n<strong>Output:</strong> 403\n<strong>Explanation:</strong> Deleting &quot;dee&quot; from &quot;delete&quot; to turn the string into &quot;let&quot;,\nadds 100[d] + 101[e] + 101[e] to the sum.\nDeleting &quot;e&quot; from &quot;leet&quot; adds 101[e] to the sum.\nAt the end, both strings are equal to &quot;let&quot;, and the answer is 100+101+101+101 = 403.\nIf instead we turned both strings into &quot;lee&quot; or &quot;eet&quot;, we would get answers of 433 or 417, which are higher.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length &lt;= 1000</code></li>\n\t<li><code>s1</code> and <code>s2</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "两个字符串的最小ASCII删除和",
            "translatedContent": "<p>给定两个字符串<code>s1</code>&nbsp;和&nbsp;<code>s2</code>，返回 <em>使两个字符串相等所需删除字符的&nbsp;<strong>ASCII&nbsp;</strong>值的最小和&nbsp;</em>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> s1 = \"sea\", s2 = \"eat\"\n<strong>输出:</strong> 231\n<strong>解释:</strong> 在 \"sea\" 中删除 \"s\" 并将 \"s\" 的值(115)加入总和。\n在 \"eat\" 中删除 \"t\" 并将 116 加入总和。\n结束时，两个字符串相等，115 + 116 = 231 就是符合条件的最小和。\n</pre>\n\n<p><strong>示例&nbsp;2:</strong></p>\n\n<pre>\n<strong>输入:</strong> s1 = \"delete\", s2 = \"leet\"\n<strong>输出:</strong> 403\n<strong>解释:</strong> 在 \"delete\" 中删除 \"dee\" 字符串变成 \"let\"，\n将 100[d]+101[e]+101[e] 加入总和。在 \"leet\" 中删除 \"e\" 将 101[e] 加入总和。\n结束时，两个字符串都等于 \"let\"，结果即为 100+101+101+101 = 403 。\n如果改为将两个字符串转换为 \"lee\" 或 \"eet\"，我们会得到 433 或 417 的结果，比答案更大。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= s1.length, s2.length &lt;= 1000</code></li>\n\t<li><code>s1</code>&nbsp;和&nbsp;<code>s2</code>&nbsp;由小写英文字母组成</li>\n</ul>\n",
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