leetcode-problemset/leetcode-cn/originData/max-difference-you-can-get-from-changing-an-integer.json

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            "title": "Max Difference You Can Get From Changing an Integer",
            "titleSlug": "max-difference-you-can-get-from-changing-an-integer",
            "content": "<p>You are given an integer <code>num</code>. You will apply the following steps to <code>num</code> <strong>two</strong> separate times:</p>\n\n<ul>\n\t<li>Pick a digit <code>x (0 &lt;= x &lt;= 9)</code>.</li>\n\t<li>Pick another digit <code>y (0 &lt;= y &lt;= 9)</code>. Note <code>y</code> can be equal to <code>x</code>.</li>\n\t<li>Replace all the occurrences of <code>x</code> in the decimal representation of <code>num</code> by <code>y</code>.</li>\n</ul>\n\n<p>Let <code>a</code> and <code>b</code> be the two results from applying the operation to <code>num</code> <em>independently</em>.</p>\n\n<p>Return <em>the max difference</em> between <code>a</code> and <code>b</code>.</p>\n\n<p>Note that neither <code>a</code> nor <code>b</code> may have any leading zeros, and <strong>must not</strong> be 0.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 555\n<strong>Output:</strong> 888\n<strong>Explanation:</strong> The first time pick x = 5 and y = 9 and store the new integer in a.\nThe second time pick x = 5 and y = 1 and store the new integer in b.\nWe have now a = 999 and b = 111 and max difference = 888\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 9\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> The first time pick x = 9 and y = 9 and store the new integer in a.\nThe second time pick x = 9 and y = 1 and store the new integer in b.\nWe have now a = 9 and b = 1 and max difference = 8\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num &lt;= 10<sup>8</sup></code></li>\n</ul>\n",
            "translatedTitle": "改变一个整数能得到的最大差值",
            "translatedContent": "<p>给你一个整数&nbsp;<code>num</code>&nbsp;。你可以对它进行以下步骤共计&nbsp;<strong>两次</strong>：</p>\n\n<ul>\n\t<li>选择一个数字&nbsp;<code>x (0&nbsp;&lt;= x &lt;= 9)</code>.</li>\n\t<li>选择另一个数字&nbsp;<code>y (0&nbsp;&lt;= y &lt;= 9)</code>&nbsp;。数字&nbsp;<code>y</code>&nbsp;可以等于&nbsp;<code>x</code>&nbsp;。</li>\n\t<li>将 <code>num</code>&nbsp;中所有出现 <code>x</code>&nbsp;的数位都用 <code>y</code>&nbsp;替换。</li>\n</ul>\n\n<p>令两次对 <code>num</code>&nbsp;的操作得到的结果分别为&nbsp;<code>a</code>&nbsp;和&nbsp;<code>b</code>&nbsp;。</p>\n\n<p>请你返回&nbsp;<code>a</code> 和&nbsp;<code>b</code>&nbsp;的 <strong>最大差值</strong> 。</p>\n\n<p>注意，<code>a</code>&nbsp;和&nbsp;<code>b</code>&nbsp;<strong>必须不能</strong> 含有前导 0，并且 <strong>不为</strong> 0。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 555\n<strong>输出：</strong>888\n<strong>解释：</strong>第一次选择 x = 5 且 y = 9 ，并把得到的新数字保存在 a 中。\n第二次选择 x = 5 且 y = 1 ，并把得到的新数字保存在 b 中。\n现在，我们有 a = 999 和 b = 111 ，最大差值为 888\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 9\n<strong>输出：</strong>8\n<strong>解释：</strong>第一次选择 x = 9 且 y = 9 ，并把得到的新数字保存在 a 中。\n第二次选择 x = 9 且 y = 1 ，并把得到的新数字保存在 b 中。\n现在，我们有 a = 9 和 b = 1 ，最大差值为 8\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 123456\n<strong>输出：</strong>820000\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 10000\n<strong>输出：</strong>80000\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 9288\n<strong>输出：</strong>8700\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num &lt;= 10^8</code></li>\n</ul>\n",
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                "Use brute force, try all possible changes and keep the minimum and maximum values."
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