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leetcode-problemset/leetcode-cn/originData/he-wei-sde-liang-ge-shu-zi-lcof.json
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{
"data": {
"question": {
"questionId": "100322",
"questionFrontendId": "LCR 179",
"categoryTitle": "Algorithms",
"boundTopicId": 87857,
"title": "查找总价格为目标值的两个商品",
"titleSlug": "he-wei-sde-liang-ge-shu-zi-lcof",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\r\n",
"translatedTitle": "查找总价格为目标值的两个商品",
"translatedContent": "<p>购物车内的商品价格按照升序记录于数组 <code>price</code>。请在购物车中找到两个商品的价格总和刚好是 <code>target</code>。若存在多种情况,返回任一结果即可。</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>price = [3, 9, 12, 15], target = 18\n<strong>输出:</strong>[3,15] 或者 [15,3]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>price = [8, 21, 27, 34, 52, 66], target = 61\n<strong>输出:</strong>[27,34] 或者 [34,27]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= price.length &lt;= 10^5</code></li>\n\t<li><code>1 &lt;= price[i] &lt;= 10^6</code></li>\n\t<li><code>1 &lt;= target &lt;= 2*10^6</code></li>\n</ul>\n",
"isPaidOnly": false,
"difficulty": "Easy",
"likes": 301,
"dislikes": 0,
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"topicTags": [
{
"name": "Array",
"slug": "array",
"translatedName": "数组",
"__typename": "TopicTagNode"
},
{
"name": "Two Pointers",
"slug": "two-pointers",
"translatedName": "双指针",
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"lang": "C++",
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"code": "class Solution {\npublic:\n vector<int> twoSum(vector<int>& price, int target) {\n \n }\n};",
"__typename": "CodeSnippetNode"
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"code": "class Solution:\n def twoSum(self, price: List[int], target: int) -> List[int]:\n ",
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"lang": "Python",
"langSlug": "python",
"code": "class Solution(object):\n def twoSum(self, price, target):\n \"\"\"\n :type price: List[int]\n :type target: int\n :rtype: List[int]\n \"\"\"\n ",
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"code": "public class Solution {\n public int[] TwoSum(int[] price, int target) {\n \n }\n}",
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{
"lang": "C",
"langSlug": "c",
"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* twoSum(int* price, int priceSize, int target, int* returnSize) {\n \n}",
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