mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-10-21 04:56:46 +08:00
181 lines
20 KiB
JSON
181 lines
20 KiB
JSON
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"title": "零钱兑换",
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"translatedTitle": "零钱兑换",
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"translatedContent": "<p>给定不同面额的硬币 <code>coins</code> 和一个总金额 <code>amount</code>。编写一个函数来计算可以凑成总金额所需的最少的硬币个数。如果没有任何一种硬币组合能组成总金额，返回 <code>-1</code>。</p>\n\n<p>你可以认为每种硬币的数量是无限的。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = <code>[1, 2, 5]</code>, amount = <code>11</code>\n<strong>输出：</strong><code>3</code> \n<strong>解释：</strong>11 = 5 + 5 + 1</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = <code>[2]</code>, amount = <code>3</code>\n<strong>输出：</strong>-1</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = [1], amount = 0\n<strong>输出：</strong>0\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = [1], amount = 1\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = [1], amount = 2\n<strong>输出：</strong>2\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= coins.length <= 12</code></li>\n\t<li><code>1 <= coins[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>0 <= amount <= 10<sup>4</sup></code></li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 322 题相同： <a href=\"https://leetcode-cn.com/problems/coin-change/\">https://leetcode-cn.com/problems/coin-change/</a></p>\n",
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