leetcode-problemset/leetcode-cn/originData/find-words-that-can-be-formed-by-characters.json

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        "question": {
            "questionId": "1112",
            "questionFrontendId": "1160",
            "categoryTitle": "Algorithms",
            "boundTopicId": 4266,
            "title": "Find Words That Can Be Formed by Characters",
            "titleSlug": "find-words-that-can-be-formed-by-characters",
            "content": "<p>You are given an array of strings <code>words</code> and a string <code>chars</code>.</p>\n\n<p>A string is <strong>good</strong> if it can be formed by characters from <code>chars</code> (each character can only be used once for <strong>each</strong> word in <code>words</code>).</p>\n\n<p>Return <em>the sum of lengths of all good strings in words</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;cat&quot;,&quot;bt&quot;,&quot;hat&quot;,&quot;tree&quot;], chars = &quot;atach&quot;\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The strings that can be formed are &quot;cat&quot; and &quot;hat&quot; so the answer is 3 + 3 = 6.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;hello&quot;,&quot;world&quot;,&quot;leetcode&quot;], chars = &quot;welldonehoneyr&quot;\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> The strings that can be formed are &quot;hello&quot; and &quot;world&quot; so the answer is 5 + 5 = 10.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length, chars.length &lt;= 100</code></li>\n\t<li><code>words[i]</code> and <code>chars</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "拼写单词",
            "translatedContent": "<p>给定一个字符串数组&nbsp;<code>words</code>&nbsp;和一个字符串 <code>chars</code>。</p>\n\n<p>如果字符串可以由 <code>chars</code> 中的字符组成（每个字符在 <strong>每个</strong>&nbsp;<code>words</code> 中只能使用一次），则认为它是好的。</p>\n\n<p>返回&nbsp;<code>words</code>&nbsp;中所有好的字符串的长度之和。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"cat\",\"bt\",\"hat\",\"tree\"], chars = \"atach\"\n<strong>输出：</strong>6\n<strong>解释： </strong>\n可以形成字符串 \"cat\" 和 \"hat\"，所以答案是 3 + 3 = 6。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"hello\",\"world\",\"leetcode\"], chars = \"welldonehoneyr\"\n<strong>输出：</strong>10\n<strong>解释：</strong>\n可以形成字符串 \"hello\" 和 \"world\"，所以答案是 5 + 5 = 10。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length, chars.length&nbsp;&lt;= 100</code></li>\n\t<li><code>words[i]</code>&nbsp;和&nbsp;<code>chars</code> 中都仅包含小写英文字母</li>\n</ul>\n",
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                    "code": "impl Solution {\n    pub fn count_characters(words: Vec<String>, chars: String) -> i32 {\n        \n    }\n}",
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                    "code": "# @param {String[]} words\n# @param {String} chars\n# @return {Integer}\ndef count_characters(words, chars)\n    \nend",
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            "hints": [
                "Solve the problem for each string in <code>words</code> independently.",
                "Now try to think in frequency of letters.",
                "Count how many times each character occurs in string <code>chars</code>.",
                "To form a string using characters from <code>chars</code>, the frequency of each character in <code>chars</code> must be greater than or equal the frequency of that character in the string to be formed."
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            "sampleTestCase": "[\"cat\",\"bt\",\"hat\",\"tree\"]\n\"atach\"",
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