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{
"data": {
"question": {
"questionId": "1276",
"questionFrontendId": "1362",
"categoryTitle": "Algorithms",
"boundTopicId": 102339,
"title": "Closest Divisors",
"titleSlug": "closest-divisors",
"content": "<p>Given an integer <code>num</code>, find the closest two integers in absolute difference whose product equals&nbsp;<code>num + 1</code>&nbsp;or <code>num + 2</code>.</p>\n\n<p>Return the two integers in any order.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 8\n<strong>Output:</strong> [3,3]\n<strong>Explanation:</strong> For num + 1 = 9, the closest divisors are 3 &amp; 3, for num + 2 = 10, the closest divisors are 2 &amp; 5, hence 3 &amp; 3 is chosen.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 123\n<strong>Output:</strong> [5,25]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 999\n<strong>Output:</strong> [40,25]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num &lt;= 10^9</code></li>\n</ul>\n",
"translatedTitle": "最接近的因数",
"translatedContent": "<p>给你一个整数&nbsp;<code>num</code>,请你找出同时满足下面全部要求的两个整数:</p>\n\n<ul>\n\t<li>两数乘积等于 &nbsp;<code>num + 1</code>&nbsp;或&nbsp;<code>num + 2</code></li>\n\t<li>以绝对差进行度量,两数大小最接近</li>\n</ul>\n\n<p>你可以按任意顺序返回这两个整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>num = 8\n<strong>输出:</strong>[3,3]\n<strong>解释:</strong>对于 num + 1 = 9最接近的两个因数是 3 &amp; 3对于 num + 2 = 10, 最接近的两个因数是 2 &amp; 5因此返回 3 &amp; 3 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><strong>输入:</strong>num = 123\n<strong>输出:</strong>[5,25]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre><strong>输入:</strong>num = 999\n<strong>输出:</strong>[40,25]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num &lt;= 10^9</code></li>\n</ul>\n",
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"Find the divisors of n+1 and n+2.",
"To find the divisors of a number, you only need to iterate to the square root of that number."
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