leetcode-problemset/leetcode-cn/originData/array-of-doubled-pairs.json

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            "title": "Array of Doubled Pairs",
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            "content": "<p>Given an integer array of even length <code>arr</code>, return <code>true</code><em> if it is possible to reorder </em><code>arr</code><em> such that </em><code>arr[2 * i + 1] = 2 * arr[2 * i]</code><em> for every </em><code>0 &lt;= i &lt; len(arr) / 2</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [3,1,3,6]\n<strong>Output:</strong> false\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [2,1,2,6]\n<strong>Output:</strong> false\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [4,-2,2,-4]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> We can take two groups, [-2,-4] and [2,4] to form [-2,-4,2,4] or [2,4,-2,-4].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= arr.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>arr.length</code> is even.</li>\n\t<li><code>-10<sup>5</sup> &lt;= arr[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "二倍数对数组",
            "translatedContent": "<p>给定一个长度为偶数的整数数组 <code>arr</code>，只有对 <code>arr</code> 进行重组后可以满足 “对于每个 <code>0 &lt;=&nbsp;i &lt; len(arr) / 2</code>，都有 <code>arr[2 * i + 1] = 2 * arr[2 * i]</code>”&nbsp;时，返回 <code>true</code>；否则，返回 <code>false</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [3,1,3,6]\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [2,1,2,6]\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr = [4,-2,2,-4]\n<strong>输出：</strong>true\n<strong>解释：</strong>可以用 [-2,-4] 和 [2,4] 这两组组成 [-2,-4,2,4] 或是 [2,4,-2,-4]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= arr.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>arr.length</code> 是偶数</li>\n\t<li><code>-10<sup>5</sup> &lt;= arr[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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