leetcode-problemset/leetcode-cn/originData/YaVDxD.json

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            "questionFrontendId": "LCR 102",
            "categoryTitle": "Algorithms",
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            "title": "目标和",
            "titleSlug": "YaVDxD",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
            "translatedTitle": "目标和",
            "translatedContent": "<p>给定一个正整数数组 <code>nums</code> 和一个整数 <code>target</code> 。</p>\n\n<p>向数组中的每个整数前添加&nbsp;<code>&#39;+&#39;</code> 或 <code>&#39;-&#39;</code> ，然后串联起所有整数，可以构造一个 <strong>表达式</strong> ：</p>\n\n<ul>\n\t<li>例如，<code>nums = [2, 1]</code> ，可以在 <code>2</code> 之前添加 <code>&#39;+&#39;</code> ，在 <code>1</code> 之前添加 <code>&#39;-&#39;</code> ，然后串联起来得到表达式 <code>&quot;+2-1&quot;</code> 。</li>\n</ul>\n\n<p>返回可以通过上述方法构造的、运算结果等于 <code>target</code> 的不同 <strong>表达式</strong> 的数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,1,1,1], target = 3\n<strong>输出：</strong>5\n<strong>解释：</strong>一共有 5 种方法让最终目标和为 3 。\n-1 + 1 + 1 + 1 + 1 = 3\n+1 - 1 + 1 + 1 + 1 = 3\n+1 + 1 - 1 + 1 + 1 = 3\n+1 + 1 + 1 - 1 + 1 = 3\n+1 + 1 + 1 + 1 - 1 = 3\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1], target = 1\n<strong>输出：</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 20</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= sum(nums[i]) &lt;= 1000</code></li>\n\t<li><code>-1000 &lt;= target &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 494&nbsp;题相同：&nbsp;<a href=\"https://leetcode-cn.com/problems/target-sum/\">https://leetcode-cn.com/problems/target-sum/</a></p>\n",
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