leetcode-problemset/leetcode/originData/subarrays-distinct-element-sum-of-squares-ii.json

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            "title": "Subarrays Distinct Element Sum of Squares II",
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            "content": "<p>You are given a <strong>0-indexed </strong>integer array <code>nums</code>.</p>\n\n<p>The <strong>distinct count</strong> of a subarray of <code>nums</code> is defined as:</p>\n\n<ul>\n\t<li>Let <code>nums[i..j]</code> be a subarray of <code>nums</code> consisting of all the indices from <code>i</code> to <code>j</code> such that <code>0 &lt;= i &lt;= j &lt; nums.length</code>. Then the number of distinct values in <code>nums[i..j]</code> is called the distinct count of <code>nums[i..j]</code>.</li>\n</ul>\n\n<p>Return <em>the sum of the <strong>squares</strong> of <strong>distinct counts</strong> of all subarrays of </em><code>nums</code>.</p>\n\n<p>Since the answer may be very large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>A subarray is a contiguous <strong>non-empty</strong> sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,1]\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> Six possible subarrays are:\n[1]: 1 distinct value\n[2]: 1 distinct value\n[1]: 1 distinct value\n[1,2]: 2 distinct values\n[2,1]: 2 distinct values\n[1,2,1]: 2 distinct values\nThe sum of the squares of the distinct counts in all subarrays is equal to 1<sup>2</sup> + 1<sup>2</sup> + 1<sup>2</sup> + 2<sup>2</sup> + 2<sup>2</sup> + 2<sup>2</sup> = 15.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,2]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Three possible subarrays are:\n[2]: 1 distinct value\n[2]: 1 distinct value\n[2,2]: 1 distinct value\nThe sum of the squares of the distinct counts in all subarrays is equal to 1<sup>2</sup> + 1<sup>2</sup> + 1<sup>2</sup> = 3.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def sumCounts(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @return Integer\n     */\n    function sumCounts($nums) {\n        \n    }\n}",
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                "Consider the sum of the count of distinct values of subarrays ending with index <code>i</code>, let’s call it <code>sum</code>. Now if you need the sum of all subarrays ending with index <code>i + 1</code> think how it can be related to <code>sum</code> and what extra will be needed to add to this.",
                "You can find that extra sum using the segment tree."
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