leetcode-problemset/leetcode/originData/minimum-window-substring.json

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            "title": "Minimum Window Substring",
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            "content": "<p>Given two strings <code>s</code> and <code>t</code> of lengths <code>m</code> and <code>n</code> respectively, return <em>the <strong>minimum window</strong></em> <span data-keyword=\"substring-nonempty\"><strong><em>substring</em></strong></span><em> of </em><code>s</code><em> such that every character in </em><code>t</code><em> (<strong>including duplicates</strong>) is included in the window</em>. If there is no such substring, return <em>the empty string </em><code>&quot;&quot;</code>.</p>\n\n<p>The testcases will be generated such that the answer is <strong>unique</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ADOBECODEBANC&quot;, t = &quot;ABC&quot;\n<strong>Output:</strong> &quot;BANC&quot;\n<strong>Explanation:</strong> The minimum window substring &quot;BANC&quot; includes &#39;A&#39;, &#39;B&#39;, and &#39;C&#39; from string t.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, t = &quot;a&quot;\n<strong>Output:</strong> &quot;a&quot;\n<strong>Explanation:</strong> The entire string s is the minimum window.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, t = &quot;aa&quot;\n<strong>Output:</strong> &quot;&quot;\n<strong>Explanation:</strong> Both &#39;a&#39;s from t must be included in the window.\nSince the largest window of s only has one &#39;a&#39;, return empty string.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == s.length</code></li>\n\t<li><code>n == t.length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of uppercase and lowercase English letters.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Could you find an algorithm that runs in <code>O(m + n)</code> time?</p>\n",
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            "exampleTestcases": "\"ADOBECODEBANC\"\n\"ABC\"\n\"a\"\n\"a\"\n\"a\"\n\"aa\"",
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                    "code": "class Solution {\npublic:\n    string minWindow(string s, string t) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def minWindow(self, s, t):\n        \"\"\"\n        :type s: str\n        :type t: str\n        :rtype: str\n        \"\"\"\n        ",
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                    "code": "class Solution {\n\n    /**\n     * @param String $s\n     * @param String $t\n     * @return String\n     */\n    function minWindow($s, $t) {\n        \n    }\n}",
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                    "code": "# @param {String} s\n# @param {String} t\n# @return {String}\ndef min_window(s, t)\n    \nend",
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                    "code": "-spec min_window(S :: unicode:unicode_binary(), T :: unicode:unicode_binary()) -> unicode:unicode_binary().\nmin_window(S, T) ->\n  .",
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            "hints": [
                "Use two pointers to create a window of letters in s, which would have all the characters from t.",
                "Expand the right pointer until all the characters of t are covered.",
                "Once all the characters are covered, move the left pointer and ensure that all the characters are still covered to minimize the subarray size.",
                "Continue expanding the right and left pointers until you reach the end of s."
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