mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
17 KiB
JSON
174 lines
17 KiB
JSON
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"question": {
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"questionId": "2081",
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"questionFrontendId": "1959",
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"title": "Minimum Total Space Wasted With K Resizing Operations",
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"content": "<p>You are currently designing a dynamic array. You are given a <strong>0-indexed</strong> integer array <code>nums</code>, where <code>nums[i]</code> is the number of elements that will be in the array at time <code>i</code>. In addition, you are given an integer <code>k</code>, the <strong>maximum</strong> number of times you can <strong>resize</strong> the array (to<strong> any</strong> size).</p>\n\n<p>The size of the array at time <code>t</code>, <code>size<sub>t</sub></code>, must be at least <code>nums[t]</code> because there needs to be enough space in the array to hold all the elements. The <strong>space wasted</strong> at time <code>t</code> is defined as <code>size<sub>t</sub> - nums[t]</code>, and the <strong>total</strong> space wasted is the <strong>sum</strong> of the space wasted across every time <code>t</code> where <code>0 <= t < nums.length</code>.</p>\n\n<p>Return <em>the <strong>minimum</strong> <strong>total space wasted</strong> if you can resize the array at most</em> <code>k</code> <em>times</em>.</p>\n\n<p><strong>Note:</strong> The array can have <strong>any size</strong> at the start and does<strong> not </strong>count towards the number of resizing operations.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20], k = 0\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> size = [20,20].\nWe can set the initial size to be 20.\nThe total wasted space is (20 - 10) + (20 - 20) = 10.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20,30], k = 1\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> size = [20,20,30].\nWe can set the initial size to be 20 and resize to 30 at time 2. \nThe total wasted space is (20 - 10) + (20 - 20) + (30 - 30) = 10.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20,15,30,20], k = 2\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> size = [10,20,20,30,30].\nWe can set the initial size to 10, resize to 20 at time 1, and resize to 30 at time 3.\nThe total wasted space is (10 - 10) + (20 - 20) + (20 - 15) + (30 - 30) + (30 - 20) = 15.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 200</code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>6</sup></code></li>\n\t<li><code>0 <= k <= nums.length - 1</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def minSpaceWastedKResizing(self, nums, k):\n \"\"\"\n :type nums: List[int]\n :type k: int\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * @param {number[]} nums\n * @param {number} k\n * @return {number}\n */\nvar minSpaceWastedKResizing = function(nums, k) {\n \n};",
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"code": "func minSpaceWastedKResizing(nums []int, k int) int {\n \n}",
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"code": "# @param {Integer[]} nums\n# @param {Integer} k\n# @return {Integer}\ndef min_space_wasted_k_resizing(nums, k)\n \nend",
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"code": "impl Solution {\n pub fn min_space_wasted_k_resizing(nums: Vec<i32>, k: i32) -> i32 {\n \n }\n}",
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"code": "-spec min_space_wasted_k_resizing(Nums :: [integer()], K :: integer()) -> integer().\nmin_space_wasted_k_resizing(Nums, K) ->\n .",
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"code": "defmodule Solution do\n @spec min_space_wasted_k_resizing(nums :: [integer], k :: integer) :: integer\n def min_space_wasted_k_resizing(nums, k) do\n \n end\nend",
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"hints": [
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"Given a range, how can you find the minimum waste if you can't perform any resize operations?",
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"Can we build our solution using dynamic programming using the current index and the number of resizing operations performed as the states?"
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],
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