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leetcode-problemset/leetcode/originData/minimum-time-to-visit-a-cell-in-a-grid.json

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"title": "Minimum Time to Visit a Cell In a Grid",
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"content": "<p>You are given a <code>m x n</code> matrix <code>grid</code> consisting of <b>non-negative</b> integers where <code>grid[row][col]</code> represents the <strong>minimum</strong> time required to be able to visit the cell <code>(row, col)</code>, which means you can visit the cell <code>(row, col)</code> only when the time you visit it is greater than or equal to <code>grid[row][col]</code>.</p>\n\n<p>You are standing in the <strong>top-left</strong> cell of the matrix in the <code>0<sup>th</sup></code> second, and you must move to <strong>any</strong> adjacent cell in the four directions: up, down, left, and right. Each move you make takes 1 second.</p>\n\n<p>Return <em>the <strong>minimum</strong> time required in which you can visit the bottom-right cell of the matrix</em>. If you cannot visit the bottom-right cell, then return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/02/14/yetgriddrawio-8.png\" /></p>\n\n<pre>\n<strong>Input:</strong> grid = [[0,1,3,2],[5,1,2,5],[4,3,8,6]]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> One of the paths that we can take is the following:\n- at t = 0, we are on the cell (0,0).\n- at t = 1, we move to the cell (0,1). It is possible because grid[0][1] &lt;= 1.\n- at t = 2, we move to the cell (1,1). It is possible because grid[1][1] &lt;= 2.\n- at t = 3, we move to the cell (1,2). It is possible because grid[1][2] &lt;= 3.\n- at t = 4, we move to the cell (1,1). It is possible because grid[1][1] &lt;= 4.\n- at t = 5, we move to the cell (1,2). It is possible because grid[1][2] &lt;= 5.\n- at t = 6, we move to the cell (1,3). It is possible because grid[1][3] &lt;= 6.\n- at t = 7, we move to the cell (2,3). It is possible because grid[2][3] &lt;= 7.\nThe final time is 7. It can be shown that it is the minimum time possible.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/02/14/yetgriddrawio-9.png\" style=\"width: 151px; height: 151px;\" /></p>\n\n<pre>\n<strong>Input:</strong> grid = [[0,2,4],[3,2,1],[1,0,4]]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> There is no path from the top left to the bottom-right cell.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>2 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>4 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= grid[i][j] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>grid[0][0] == 0</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<style type=\"text/css\">.spoilerbutton {display:block; border:dashed; padding: 0px 0px; margin:10px 0px; font-size:150%; font-weight: bold; color:#000000; background-color:cyan; outline:0; \n}\n.spoiler {overflow:hidden;}\n.spoiler > div {-webkit-transition: all 0s ease;-moz-transition: margin 0s ease;-o-transition: all 0s ease;transition: margin 0s ease;}\n.spoilerbutton[value=\"Show Message\"] + .spoiler > div {margin-top:-500%;}\n.spoilerbutton[value=\"Hide Message\"] + .spoiler {padding:5px;}\n</style>\n",
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"Try using some algorithm that can find the shortest paths on a graph.",
"Consider the case where you have to go back and forth between two cells of the matrix to unlock some other cells."
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