mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
18 KiB
JSON
186 lines
18 KiB
JSON
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"questionId": "2718",
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"title": "Minimum Operations to Make All Array Elements Equal",
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"content": "<p>You are given an array <code>nums</code> consisting of positive integers.</p>\n\n<p>You are also given an integer array <code>queries</code> of size <code>m</code>. For the <code>i<sup>th</sup></code> query, you want to make all of the elements of <code>nums</code> equal to<code> queries[i]</code>. You can perform the following operation on the array <strong>any</strong> number of times:</p>\n\n<ul>\n\t<li><strong>Increase</strong> or <strong>decrease</strong> an element of the array by <code>1</code>.</li>\n</ul>\n\n<p>Return <em>an array </em><code>answer</code><em> of size </em><code>m</code><em> where </em><code>answer[i]</code><em> is the <strong>minimum</strong> number of operations to make all elements of </em><code>nums</code><em> equal to </em><code>queries[i]</code>.</p>\n\n<p><strong>Note</strong> that after each query the array is reset to its original state.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,6,8], queries = [1,5]\n<strong>Output:</strong> [14,10]\n<strong>Explanation:</strong> For the first query we can do the following operations:\n- Decrease nums[0] 2 times, so that nums = [1,1,6,8].\n- Decrease nums[2] 5 times, so that nums = [1,1,1,8].\n- Decrease nums[3] 7 times, so that nums = [1,1,1,1].\nSo the total number of operations for the first query is 2 + 5 + 7 = 14.\nFor the second query we can do the following operations:\n- Increase nums[0] 2 times, so that nums = [5,1,6,8].\n- Increase nums[1] 4 times, so that nums = [5,5,6,8].\n- Decrease nums[2] 1 time, so that nums = [5,5,5,8].\n- Decrease nums[3] 3 times, so that nums = [5,5,5,5].\nSo the total number of operations for the second query is 2 + 4 + 1 + 3 = 10.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,9,6,3], queries = [10]\n<strong>Output:</strong> [20]\n<strong>Explanation:</strong> We can increase each value in the array to 10. The total number of operations will be 8 + 1 + 4 + 7 = 20.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == queries.length</code></li>\n\t<li><code>1 <= n, m <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i], queries[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"categoryTitle": "Algorithms",
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"code": "class Solution {\n\n /**\n * @param Integer[] $nums\n * @param Integer[] $queries\n * @return Integer[]\n */\n function minOperations($nums, $queries) {\n \n }\n}",
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"For each query, you should decrease all elements greater than queries[i] and increase all elements less than queries[i].",
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"The answer is the sum of absolute differences between queries[i] and every element of the array. How do you calculate that optimally?"
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