leetcode-problemset/leetcode/originData/longest-unequal-adjacent-groups-subsequence-ii.json

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            "title": "Longest Unequal Adjacent Groups Subsequence II",
            "titleSlug": "longest-unequal-adjacent-groups-subsequence-ii",
            "content": "<p>You are given an integer <code>n</code>, a <strong>0-indexed</strong> string array <code>words</code>, and a <strong>0-indexed</strong> array <code>groups</code>, both arrays having length <code>n</code>.</p>\n\n<p>The <strong>hamming distance</strong> between two strings of equal length is the number of positions at which the corresponding characters are <strong>different</strong>.</p>\n\n<p>You need to select the <strong>longest</strong> <strong>subsequence</strong> from an array of indices <code>[0, 1, ..., n - 1]</code>, such that for the subsequence denoted as <code>[i<sub>0</sub>, i<sub>1</sub>, ..., i<sub>k - 1</sub>]</code> having length <code>k</code>, the following holds:</p>\n\n<ul>\n\t<li>For <strong>adjacent</strong> indices in the subsequence, their corresponding groups are <strong>unequal</strong>, i.e., <code>groups[i<sub>j</sub>] != groups[i<sub>j + 1</sub>]</code>, for each <code>j</code> where <code>0 &lt; j + 1 &lt; k</code>.</li>\n\t<li><code>words[i<sub>j</sub>]</code> and <code>words[i<sub>j + 1</sub>]</code> are <strong>equal</strong> in length, and the <strong>hamming distance</strong> between them is <code>1</code>, where <code>0 &lt; j + 1 &lt; k</code>, for all indices in the subsequence.</li>\n</ul>\n\n<p>Return <em>a string array containing the words corresponding to the indices <strong>(in order)</strong> in the selected subsequence</em>. If there are multiple answers, return <em>any of them</em>.</p>\n\n<p>A <strong>subsequence</strong> of an array is a new array that is formed from the original array by deleting some (possibly none) of the elements without disturbing the relative positions of the remaining elements.</p>\n\n<p><strong>Note:</strong> strings in <code>words</code> may be <strong>unequal</strong> in length.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, words = [&quot;bab&quot;,&quot;dab&quot;,&quot;cab&quot;], groups = [1,2,2]\n<strong>Output:</strong> [&quot;bab&quot;,&quot;cab&quot;]\n<strong>Explanation:</strong> A subsequence that can be selected is [0,2].\n- groups[0] != groups[2]\n- words[0].length == words[2].length, and the hamming distance between them is 1.\nSo, a valid answer is [words[0],words[2]] = [&quot;bab&quot;,&quot;cab&quot;].\nAnother subsequence that can be selected is [0,1].\n- groups[0] != groups[1]\n- words[0].length == words[1].length, and the hamming distance between them is 1.\nSo, another valid answer is [words[0],words[1]] = [&quot;bab&quot;,&quot;dab&quot;].\nIt can be shown that the length of the longest subsequence of indices that satisfies the conditions is 2.  </pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4, words = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;d&quot;], groups = [1,2,3,4]\n<strong>Output:</strong> [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;d&quot;]\n<strong>Explanation:</strong> We can select the subsequence [0,1,2,3].\nIt satisfies both conditions.\nHence, the answer is [words[0],words[1],words[2],words[3]] = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;,&quot;d&quot;].\nIt has the longest length among all subsequences of indices that satisfy the conditions.\nHence, it is the only answer.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == words.length == groups.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>1 &lt;= groups[i] &lt;= n</code></li>\n\t<li><code>words</code> consists of <strong>distinct</strong> strings.</li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<string> getWordsInLongestSubsequence(int n, vector<string>& words, vector<int>& groups) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public List<String> getWordsInLongestSubsequence(int n, String[] words, int[] groups) {\n        \n    }\n}",
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                    "lang": "Python",
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                    "code": "class Solution(object):\n    def getWordsInLongestSubsequence(self, n, words, groups):\n        \"\"\"\n        :type n: int\n        :type words: List[str]\n        :type groups: List[int]\n        :rtype: List[str]\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def getWordsInLongestSubsequence(self, n: int, words: List[str], groups: List[int]) -> List[str]:\n        ",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** getWordsInLongestSubsequence(int n, char** words, int wordsSize, int* groups, int groupsSize, int* returnSize){\n\n}",
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                    "code": "public class Solution {\n    public IList<string> GetWordsInLongestSubsequence(int n, string[] words, int[] groups) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number} n\n * @param {string[]} words\n * @param {number[]} groups\n * @return {string[]}\n */\nvar getWordsInLongestSubsequence = function(n, words, groups) {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $n\n     * @param String[] $words\n     * @param Integer[] $groups\n     * @return String[]\n     */\n    function getWordsInLongestSubsequence($n, $words, $groups) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func getWordsInLongestSubsequence(_ n: Int, _ words: [String], _ groups: [Int]) -> [String] {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun getWordsInLongestSubsequence(n: Int, words: Array<String>, groups: IntArray): List<String> {\n        \n    }\n}",
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                    "lang": "Dart",
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                    "code": "class Solution {\n  List<String> getWordsInLongestSubsequence(int n, List<String> words, List<int> groups) {\n\n  }\n}",
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                    "lang": "Go",
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                    "code": "func getWordsInLongestSubsequence(n int, words []string, groups []int) []string {\n    \n}",
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                    "code": "# @param {Integer} n\n# @param {String[]} words\n# @param {Integer[]} groups\n# @return {String[]}\ndef get_words_in_longest_subsequence(n, words, groups)\n    \nend",
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                    "code": "object Solution {\n    def getWordsInLongestSubsequence(n: Int, words: Array[String], groups: Array[Int]): List[String] = {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn get_words_in_longest_subsequence(n: i32, words: Vec<String>, groups: Vec<i32>) -> Vec<String> {\n        \n    }\n}",
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                    "code": "-spec get_words_in_longest_subsequence(N :: integer(), Words :: [unicode:unicode_binary()], Groups :: [integer()]) -> [unicode:unicode_binary()].\nget_words_in_longest_subsequence(N, Words, Groups) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec get_words_in_longest_subsequence(n :: integer, words :: [String.t], groups :: [integer]) :: [String.t]\n  def get_words_in_longest_subsequence(n, words, groups) do\n\n  end\nend",
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                "Let <code>dp[i]</code> represent the length of the longest subsequence ending with <code>words[i]</code> that satisfies the conditions.",
                "<code>dp[i] =</code> (maximum value of <code>dp[j]</code>) <code>+ 1</code> for indices <code>j < i</code>, where <code>groups[i] != groups[j]</code>, <code>words[i]</code> and <code>words[j]</code> are equal in length, and the hamming distance between <code>words[i]</code> and <code>words[j]</code> is exactly <code>1</code>.",
                "Keep track of the <code>j</code> values used to achieve the maximum <code>dp[i]</code> for each index <code>i</code>.",
                "The expected array's length is <code>max(dp[0:n])</code>, and starting from the index having the maximum value in <code>dp</code>, we can trace backward to get the words."
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