mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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188 lines
18 KiB
JSON
188 lines
18 KiB
JSON
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"questionId": "1762",
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"title": "Furthest Building You Can Reach",
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"content": "<p>You are given an integer array <code>heights</code> representing the heights of buildings, some <code>bricks</code>, and some <code>ladders</code>.</p>\n\n<p>You start your journey from building <code>0</code> and move to the next building by possibly using bricks or ladders.</p>\n\n<p>While moving from building <code>i</code> to building <code>i+1</code> (<strong>0-indexed</strong>),</p>\n\n<ul>\n\t<li>If the current building's height is <strong>greater than or equal</strong> to the next building's height, you do <strong>not</strong> need a ladder or bricks.</li>\n\t<li>If the current building's height is <b>less than</b> the next building's height, you can either use <strong>one ladder</strong> or <code>(h[i+1] - h[i])</code> <strong>bricks</strong>.</li>\n</ul>\n\n<p><em>Return the furthest building index (0-indexed) you can reach if you use the given ladders and bricks optimally.</em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/27/q4.gif\" style=\"width: 562px; height: 561px;\" />\n<pre>\n<strong>Input:</strong> heights = [4,2,7,6,9,14,12], bricks = 5, ladders = 1\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> Starting at building 0, you can follow these steps:\n- Go to building 1 without using ladders nor bricks since 4 >= 2.\n- Go to building 2 using 5 bricks. You must use either bricks or ladders because 2 < 7.\n- Go to building 3 without using ladders nor bricks since 7 >= 6.\n- Go to building 4 using your only ladder. You must use either bricks or ladders because 6 < 9.\nIt is impossible to go beyond building 4 because you do not have any more bricks or ladders.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> heights = [4,12,2,7,3,18,20,3,19], bricks = 10, ladders = 2\n<strong>Output:</strong> 7\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> heights = [14,3,19,3], bricks = 17, ladders = 0\n<strong>Output:</strong> 3\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= heights.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= heights[i] <= 10<sup>6</sup></code></li>\n\t<li><code>0 <= bricks <= 10<sup>9</sup></code></li>\n\t<li><code>0 <= ladders <= heights.length</code></li>\n</ul>\n",
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"code": "# @param {Integer[]} heights\n# @param {Integer} bricks\n# @param {Integer} ladders\n# @return {Integer}\ndef furthest_building(heights, bricks, ladders)\n \nend",
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"Assume the problem is to check whether you can reach the last building or not.",
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"You'll have to do a set of jumps, and choose for each one whether to do it using a ladder or bricks. It's always optimal to use ladders in the largest jumps.",
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"Iterate on the buildings, maintaining the largest r jumps and the sum of the remaining ones so far, and stop whenever this sum exceeds b."
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