leetcode-problemset/leetcode/originData/find-the-k-or-of-an-array.json

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            "title": "Find the K-or of an Array",
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            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>, and an integer <code>k</code>.</p>\n\n<p>The <strong>K-or</strong> of <code>nums</code> is a non-negative integer that satisfies the following:</p>\n\n<ul>\n\t<li>The <code>i<sup>th</sup></code> bit is set in the K-or <strong>if and only if</strong> there are at least <code>k</code> elements of nums in which bit <code>i</code> is set.</li>\n</ul>\n\n<p>Return <em>the <strong> K-or</strong> of</em> <code>nums</code>.</p>\n\n<p><strong>Note</strong> that a bit <code>i</code> is set in <code>x</code> if <code>(2<sup>i</sup> AND x) == 2<sup>i</sup></code>, where <code>AND</code> is the bitwise <code>AND</code> operator.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [7,12,9,8,9,15], k = 4\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> Bit 0 is set at nums[0], nums[2], nums[4], and nums[5].\nBit 1 is set at nums[0], and nums[5].\nBit 2 is set at nums[0], nums[1], and nums[5].\nBit 3 is set at nums[1], nums[2], nums[3], nums[4], and nums[5].\nOnly bits 0 and 3 are set in at least k elements of the array, and bits i &gt;= 4 are not set in any of the array&#39;s elements. Hence, the answer is 2^0 + 2^3 = 9.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,12,1,11,4,5], k = 6\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> Since k == 6 == nums.length, the 6-or of the array is equal to the bitwise AND of all its elements. Hence, the answer is 2 AND 12 AND 1 AND 11 AND 4 AND 5 = 0.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,8,5,9,11,6,8], k = 1\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> Since k == 1, the 1-or of the array is equal to the bitwise OR of all its elements. Hence, the answer is 10 OR 8 OR 5 OR 9 OR 11 OR 6 OR 8 = 15.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>0 &lt;= nums[i] &lt; 2<sup>31</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int findKOr(vector<int>& nums, int k) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def findKOr(self, nums, k):\n        \"\"\"\n        :type nums: List[int]\n        :type k: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "public class Solution {\n    public int FindKOr(int[] nums, int k) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @param {number} k\n * @return {number}\n */\nvar findKOr = function(nums, k) {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @param Integer $k\n     * @return Integer\n     */\n    function findKOr($nums, $k) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func findKOr(_ nums: [Int], _ k: Int) -> Int {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun findKOr(nums: IntArray, k: Int): Int {\n        \n    }\n}",
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                    "code": "# @param {Integer[]} nums\n# @param {Integer} k\n# @return {Integer}\ndef find_k_or(nums, k)\n    \nend",
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                    "code": "impl Solution {\n    pub fn find_k_or(nums: Vec<i32>, k: i32) -> i32 {\n        \n    }\n}",
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                    "lang": "Racket",
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                    "code": "defmodule Solution do\n  @spec find_k_or(nums :: [integer], k :: integer) :: integer\n  def find_k_or(nums, k) do\n    \n  end\nend",
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                "Fix a <code>bit</code> from the range <code>[0, 31]</code>, then count the number of elements of <code>nums</code> that have <code>bit</code> set in them.",
                "<code>bit</code> is set in integer <code>x</code> if and only if <code>2<sup>bit</sup> AND x == 2<sup>bit</sup></code>, where <code>AND</code> is the bitwise <code>AND</code> operation.",
                "Fix a <code>bit</code> from the range <code>[0, 31]</code>, then count the number of elements of <code>nums</code> that have <code>bit</code> set in them.",
                "<code>bit</code> is set in integer <code>x</code> if and only if <code>2<sup>bit</sup> AND x == 2<sup>bit</sup></code>, where <code>AND</code> is the bitwise <code>AND</code> operation."
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