leetcode-problemset/leetcode/originData/count-pairs-of-points-with-distance-k.json

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            "questionId": "2953",
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            "title": "Count Pairs of Points With Distance k",
            "titleSlug": "count-pairs-of-points-with-distance-k",
            "content": "<p>You are given a <strong>2D</strong> integer array <code>coordinates</code> and an integer <code>k</code>, where <code>coordinates[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> are the coordinates of the <code>i<sup>th</sup></code> point in a 2D plane.</p>\n\n<p>We define the <strong>distance</strong> between two points <code>(x<sub>1</sub>, y<sub>1</sub>)</code> and <code>(x<sub>2</sub>, y<sub>2</sub>)</code> as <code>(x1 XOR x2) + (y1 XOR y2)</code> where <code>XOR</code> is the bitwise <code>XOR</code> operation.</p>\n\n<p>Return <em>the number of pairs </em><code>(i, j)</code><em> such that </em><code>i &lt; j</code><em> and the distance between points </em><code>i</code><em> and </em><code>j</code><em> is equal to </em><code>k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> coordinates = [[1,2],[4,2],[1,3],[5,2]], k = 5\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We can choose the following pairs:\n- (0,1): Because we have (1 XOR 4) + (2 XOR 2) = 5.\n- (2,3): Because we have (1 XOR 5) + (3 XOR 2) = 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> coordinates = [[1,3],[1,3],[1,3],[1,3],[1,3]], k = 0\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> Any two chosen pairs will have a distance of 0. There are 10 ways to choose two pairs.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= coordinates.length &lt;= 50000</code></li>\n\t<li><code>0 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>6</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 100</code></li>\n</ul>\n",
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            "categoryTitle": "Algorithms",
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                    "name": "Array",
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                    "name": "Hash Table",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int countPairs(vector<vector<int>>& coordinates, int k) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int countPairs(List<List<Integer>> coordinates, int k) {\n        \n    }\n}",
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                    "lang": "Python",
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                    "code": "class Solution(object):\n    def countPairs(self, coordinates, k):\n        \"\"\"\n        :type coordinates: List[List[int]]\n        :type k: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "lang": "Python3",
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                    "code": "class Solution:\n    def countPairs(self, coordinates: List[List[int]], k: int) -> int:\n        ",
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                    "lang": "C",
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                    "code": "int countPairs(int** coordinates, int coordinatesSize, int* coordinatesColSize, int k){\n\n}",
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                    "lang": "C#",
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                    "code": "public class Solution {\n    public int CountPairs(IList<IList<int>> coordinates, int k) {\n        \n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number[][]} coordinates\n * @param {number} k\n * @return {number}\n */\nvar countPairs = function(coordinates, k) {\n    \n};",
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                    "code": "function countPairs(coordinates: number[][], k: number): number {\n\n};",
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                    "lang": "PHP",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[][] $coordinates\n     * @param Integer $k\n     * @return Integer\n     */\n    function countPairs($coordinates, $k) {\n        \n    }\n}",
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                    "lang": "Swift",
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                    "code": "class Solution {\n    func countPairs(_ coordinates: [[Int]], _ k: Int) -> Int {\n        \n    }\n}",
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                    "lang": "Kotlin",
                    "langSlug": "kotlin",
                    "code": "class Solution {\n    fun countPairs(coordinates: List<List<Int>>, k: Int): Int {\n        \n    }\n}",
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                    "lang": "Dart",
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                    "code": "class Solution {\n  int countPairs(List<List<int>> coordinates, int k) {\n\n  }\n}",
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                    "lang": "Go",
                    "langSlug": "golang",
                    "code": "func countPairs(coordinates [][]int, k int) int {\n    \n}",
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                    "lang": "Ruby",
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                    "code": "# @param {Integer[][]} coordinates\n# @param {Integer} k\n# @return {Integer}\ndef count_pairs(coordinates, k)\n    \nend",
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                    "lang": "Scala",
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                    "code": "object Solution {\n    def countPairs(coordinates: List[List[Int]], k: Int): Int = {\n        \n    }\n}",
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                    "lang": "Rust",
                    "langSlug": "rust",
                    "code": "impl Solution {\n    pub fn count_pairs(coordinates: Vec<Vec<i32>>, k: i32) -> i32 {\n        \n    }\n}",
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                {
                    "lang": "Racket",
                    "langSlug": "racket",
                    "code": "(define/contract (count-pairs coordinates k)\n  (-> (listof (listof exact-integer?)) exact-integer? exact-integer?)\n\n  )",
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                    "lang": "Erlang",
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                    "code": "-spec count_pairs(Coordinates :: [[integer()]], K :: integer()) -> integer().\ncount_pairs(Coordinates, K) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec count_pairs(coordinates :: [[integer]], k :: integer) :: integer\n  def count_pairs(coordinates, k) do\n\n  end\nend",
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            "hints": [
                "<div class=\"_1l1MA\">Suppose that <code>x = x<sub>1</sub> XOR x<sub>2</sub></code> and y = y<sub>1</sub> XOR y<sub>2</sub> then we can get <code>x<sub>2</sub> = x XOR x<sub>1</sub></code> and <code>y<sub>2</sub> = y XOR y<sub>1</sub></code>.</div>",
                "<div class=\"_1l1MA\">We are supposed to have k = x + y so we can get <code>x<sub>2</sub> = x XOR x<sub>1</sub></code> and <code>y<sub>2</sub> = (k - x) XOR y<sub>1</sub></code>.</div>",
                "<div class=\"_1l1MA\">We can iterate over all possible values of <code>x</code> and count the number of points <code>(x<sub>1</sub>, x<sub>2</sub>)</code> and <code>(x<sub>2</sub>, y<sub>2</sub>)</code>.</div>"
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