leetcode-problemset/leetcode/originData/count-number-of-bad-pairs.json

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            "title": "Count Number of Bad Pairs",
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            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>. A pair of indices <code>(i, j)</code> is a <strong>bad pair</strong> if <code>i &lt; j</code> and <code>j - i != nums[j] - nums[i]</code>.</p>\n\n<p>Return<em> the total number of <strong>bad pairs</strong> in </em><code>nums</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,1,3,3]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The pair (0, 1) is a bad pair since 1 - 0 != 1 - 4.\nThe pair (0, 2) is a bad pair since 2 - 0 != 3 - 4, 2 != -1.\nThe pair (0, 3) is a bad pair since 3 - 0 != 3 - 4, 3 != -1.\nThe pair (1, 2) is a bad pair since 2 - 1 != 3 - 1, 1 != 2.\nThe pair (2, 3) is a bad pair since 3 - 2 != 3 - 3, 1 != 0.\nThere are a total of 5 bad pairs, so we return 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There are no bad pairs.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    long long countBadPairs(vector<int>& nums) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public long countBadPairs(int[] nums) {\n        \n    }\n}",
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                    "code": "class Solution(object):\n    def countBadPairs(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def countBadPairs(self, nums: List[int]) -> int:\n        ",
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                    "code": "long long countBadPairs(int* nums, int numsSize) {\n    \n}",
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                    "code": "public class Solution {\n    public long CountBadPairs(int[] nums) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @return {number}\n */\nvar countBadPairs = function(nums) {\n    \n};",
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                    "code": "function countBadPairs(nums: number[]): number {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @return Integer\n     */\n    function countBadPairs($nums) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func countBadPairs(_ nums: [Int]) -> Int {\n        \n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "class Solution {\n    fun countBadPairs(nums: IntArray): Long {\n        \n    }\n}",
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                    "lang": "Go",
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                    "code": "func countBadPairs(nums []int) int64 {\n    \n}",
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                    "code": "# @param {Integer[]} nums\n# @return {Integer}\ndef count_bad_pairs(nums)\n    \nend",
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                    "code": "impl Solution {\n    pub fn count_bad_pairs(nums: Vec<i32>) -> i64 {\n        \n    }\n}",
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                    "lang": "Racket",
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                    "code": "defmodule Solution do\n  @spec count_bad_pairs(nums :: [integer]) :: integer\n  def count_bad_pairs(nums) do\n    \n  end\nend",
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            "hints": [
                "Would it be easier to count the number of pairs that are not bad pairs?",
                "Notice that (j - i != nums[j] - nums[i]) is the same as (nums[i] - i != nums[j] - j).",
                "Keep a counter of nums[i] - i. To be efficient, use a HashMap."
            ],
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