mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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59 lines
12 KiB
JSON
59 lines
12 KiB
JSON
{
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"questionId": "2821",
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"questionFrontendId": "2715",
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"categoryTitle": "JavaScript",
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"boundTopicId": 2293968,
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"title": "Timeout Cancellation",
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"titleSlug": "timeout-cancellation",
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"content": "<p>Given a function <code>fn</code>, an array of arguments <code>args</code>, and a timeout <code>t</code> in milliseconds, return a cancel function <code>cancelFn</code>.</p>\n\n<p>After a delay of <code>cancelTimeMs</code>, the returned cancel function <code>cancelFn</code> will be invoked.</p>\n\n<pre>\nsetTimeout(cancelFn, cancelTimeMs)\n</pre>\n\n<p>Initially, the execution of the function <code>fn</code> should be delayed by <code>t</code> milliseconds.</p>\n\n<p>If, before the delay of <code>t</code> milliseconds, the function <code>cancelFn</code> is invoked, it should cancel the delayed execution of <code>fn</code>. Otherwise, if <code>cancelFn</code> is not invoked within the specified delay <code>t</code>, <code>fn</code> should be executed with the provided <code>args</code> as arguments.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x) => x * 5, args = [2], t = 20\n<strong>Output:</strong> [{"time": 20, "returned": 10}]\n<strong>Explanation:</strong> \nconst cancelTimeMs = 50;\nconst result = [];\n\nconst fn = (x) => x * 5;\n\nconst start = performance.now();\n\nconst log = (...argsArr) => {\n const diff = Math.floor(performance.now() - start);\n result.push({"time": diff, "returned": fn(...argsArr)});\n}\n \nconst cancel = cancellable(log, [2], 20);\n\nconst maxT = Math.max(t, 50);\n \nsetTimeout(cancel, cancelTimeMs);\n\nsetTimeout(() => {\n console.log(result); // [{"time":20,"returned":10}]\n}, maxT + 15);\n\nThe cancellation was scheduled to occur after a delay of cancelTimeMs (50ms), which happened after the execution of fn(2) at 20ms.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x) => x**2, args = [2], t = 100\n<strong>Output:</strong> []\n<strong>Explanation:</strong> \nconst cancelTimeMs = 50;\nThe cancellation was scheduled to occur after a delay of cancelTimeMs (50ms), which happened before the execution of fn(2) at 100ms, resulting in fn(2) never being called.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x1, x2) => x1 * x2, args = [2,4], t = 30\n<strong>Output:</strong> [{"time": 30, "returned": 8}]\n<strong>Explanation: \n</strong>const cancelTimeMs = 100;\nThe cancellation was scheduled to occur after a delay of cancelTimeMs (100ms), which happened after the execution of fn(2,4) at 30ms.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>fn</code> is a function</li>\n\t<li><code>args</code> is a valid JSON array</li>\n\t<li><code>1 <= args.length <= 10</code></li>\n\t<li><code><font face=\"monospace\">20 <= t <= 1000</font></code></li>\n\t<li><code><font face=\"monospace\">10 <= cancelTimeMs <= 1000</font></code></li>\n</ul>\n",
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"translatedTitle": "执行可取消的延迟函数",
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"translatedContent": "<p>现给定一个函数 <code>fn</code> ,一个参数数组 <code>args</code> 和一个以毫秒为单位的超时时间 <code>t</code> ,返回一个取消函数 <code>cancelFn</code> 。</p>\n\n<p>在经过 <code>t</code> 毫秒的延迟后,应该调用 <code>fn</code> 函数,并将 <code>args</code> 作为参数传递。<strong>除非</strong> 在 <code>t</code> 毫秒的延迟过程中,在 <code>cancelT</code> 毫秒时调用了 <code>cancelFn</code>。并且在这种情况下,<code>fn</code> 函数不应该被调用。</p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<pre>\n<b>输入:</b>fn = (x) => x * 5, args = [2], t = 20, cancelT = 50\n<b>输出:</b>[{\"time\": 20, \"returned\": 10}]\n<b>解释:</b>\nconst cancel = cancellable((x) => x * 5, [2], 20); // fn(2) 在 t=20ms 时被调用\nsetTimeout(cancel, 50);\n\n取消操作被安排在延迟了 cancelT(50毫秒)后进行,这发生在 fn(2) 在20毫秒时执行之后。</pre>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<pre>\n<b>输入:</b>fn = (x) => x**2, args = [2], t = 100, cancelT = 50\n<b>输出:</b>[]\n<b>解释:</b>\nconst cancel = cancellable((x) => x**2, [2], 100); // fn(2) 没被调用\nsetTimeout(cancel, 50);\n\n取消操作被安排在延迟了 cancelT(50毫秒)后进行,这发生在 fn(2) 在100毫秒时执行之前,导致 fn(2) 从未被调用。\n</pre>\n\n<p><strong class=\"example\">示例 3:</strong></p>\n\n<pre>\n<b>输入:</b>fn = (x1, x2) => x1 * x2, args = [2,4], t = 30, cancelTime = 100\n<b>输出:</b>[{\"time\": 30, \"returned\": 8}]\n<b>解释:</b>\nconst cancel = cancellable((x1, x2) => x1 * x2, [2,4], 30); // fn(2,4) 在 t=30ms 时被调用\nsetTimeout(cancel, 100);\n\n取消操作被安排在延迟了 cancelT(100毫秒)后进行,这发生在 fn(2,4) 在30毫秒时执行之后。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>fn</code> 是一个函数</li>\n\t<li><code>args</code> 是一个有效的 JSON 数组</li>\n\t<li><code>1 <= args.length <= 10</code></li>\n\t<li><code><font face=\"monospace\">20 <= t <= 1000</font></code></li>\n\t<li><code><font face=\"monospace\">10 <= cancelT <= 1000</font></code></li>\n</ul>\n",
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