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leetcode-problemset/leetcode-cn/originData/sum-of-digits-in-base-k.json

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{
"data": {
"question": {
"questionId": "1965",
"questionFrontendId": "1837",
"categoryTitle": "Algorithms",
"boundTopicId": 736565,
"title": "Sum of Digits in Base K",
"titleSlug": "sum-of-digits-in-base-k",
"content": "<p>Given an integer <code>n</code> (in base <code>10</code>) and a base <code>k</code>, return <em>the <strong>sum</strong> of the digits of </em><code>n</code><em> <strong>after</strong> converting </em><code>n</code><em> from base </em><code>10</code><em> to base </em><code>k</code>.</p>\n\n<p>After converting, each digit should be interpreted as a base <code>10</code> number, and the sum should be returned in base <code>10</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 34, k = 6\n<strong>Output:</strong> 9\n<strong>Explanation: </strong>34 (base 10) expressed in base 6 is 54. 5 + 4 = 9.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 10, k = 10\n<strong>Output:</strong> 1\n<strong>Explanation: </strong>n is already in base 10. 1 + 0 = 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>2 &lt;= k &lt;= 10</code></li>\n</ul>\n",
"translatedTitle": "K 进制表示下的各位数字总和",
"translatedContent": "<p>给你一个整数 <code>n</code><code>10</code> 进制)和一个基数 <code>k</code> ,请你将 <code>n</code> 从 <code>10</code> 进制表示转换为 <code>k</code> 进制表示,计算并返回转换后各位数字的 <strong>总和</strong> 。</p>\n\n<p>转换后,各位数字应当视作是 <code>10</code> 进制数字,且它们的总和也应当按 <code>10</code> 进制表示返回。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 34, k = 6\n<strong>输出:</strong>9\n<strong>解释:</strong>34 (10 进制) 在 6 进制下表示为 54 。5 + 4 = 9 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 10, k = 10\n<strong>输出:</strong>1\n<strong>解释:</strong>n 本身就是 10 进制。 1 + 0 = 1 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 100</code></li>\n\t<li><code>2 <= k <= 10</code></li>\n</ul>\n",
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"hints": [
"Convert the given number into base k.",
"Use mod-10 to find what each digit is after the conversion and sum the digits."
],
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