leetcode-problemset/leetcode-cn/originData/subarray-sums-divisible-by-k.json

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            "title": "Subarray Sums Divisible by K",
            "titleSlug": "subarray-sums-divisible-by-k",
            "content": "<p>Given an integer array <code>nums</code> and an integer <code>k</code>, return <em>the number of non-empty <strong>subarrays</strong> that have a sum divisible by </em><code>k</code>.</p>\n\n<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,5,0,-2,-3,1], k = 5\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> There are 7 subarrays with a sum divisible by k = 5:\n[4, 5, 0, -2, -3, 1], [5], [5, 0], [5, 0, -2, -3], [0], [0, -2, -3], [-2, -3]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5], k = 9\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>2 &lt;= k &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "和可被 K 整除的子数组",
            "translatedContent": "<p>给定一个整数数组 <code>nums</code>&nbsp;和一个整数 <code>k</code> ，返回其中元素之和可被 <code>k</code>&nbsp;整除的（连续、非空） <strong>子数组</strong> 的数目。</p>\n\n<p><strong>子数组</strong> 是数组的 <strong>连续</strong> 部分。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [4,5,0,-2,-3,1], k = 5\n<strong>输出：</strong>7\n<strong>解释：\n</strong>有 7 个子数组满足其元素之和可被 k = 5 整除：\n[4, 5, 0, -2, -3, 1], [5], [5, 0], [5, 0, -2, -3], [0], [0, -2, -3], [-2, -3]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [5], k = 9\n<strong>输出:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup>&nbsp;&lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>2 &lt;= k &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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