leetcode-problemset/leetcode-cn/originData/steps-to-make-array-non-decreasing.json

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            "title": "Steps to Make Array Non-decreasing",
            "titleSlug": "steps-to-make-array-non-decreasing",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>. In one step, <strong>remove</strong> all elements <code>nums[i]</code> where <code>nums[i - 1] &gt; nums[i]</code> for all <code>0 &lt; i &lt; nums.length</code>.</p>\n\n<p>Return <em>the number of steps performed until </em><code>nums</code><em> becomes a <strong>non-decreasing</strong> array</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,3,4,4,7,3,6,11,8,5,11]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The following are the steps performed:\n- Step 1: [5,<strong><u>3</u></strong>,4,4,7,<u><strong>3</strong></u>,6,11,<u><strong>8</strong></u>,<u><strong>5</strong></u>,11] becomes [5,4,4,7,6,11,11]\n- Step 2: [5,<u><strong>4</strong></u>,4,7,<u><strong>6</strong></u>,11,11] becomes [5,4,7,11,11]\n- Step 3: [5,<u><strong>4</strong></u>,7,11,11] becomes [5,7,11,11]\n[5,7,11,11] is a non-decreasing array. Therefore, we return 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,5,7,7,13]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> nums is already a non-decreasing array. Therefore, we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "使数组按非递减顺序排列",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 。在一步操作中，移除所有满足&nbsp;<code>nums[i - 1] &gt; nums[i]</code> 的 <code>nums[i]</code> ，其中 <code>0 &lt; i &lt; nums.length</code> 。</p>\n\n<p>重复执行步骤，直到 <code>nums</code> 变为 <strong>非递减</strong> 数组，返回所需执行的操作数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [5,3,4,4,7,3,6,11,8,5,11]\n<strong>输出：</strong>3\n<strong>解释：</strong>执行下述几个步骤：\n- 步骤 1 ：[5,<em><strong>3</strong></em>,4,4,7,<em><strong>3</strong></em>,6,11,<em><strong>8</strong></em>,<em><strong>5</strong></em>,11] 变为 [5,4,4,7,6,11,11]\n- 步骤 2 ：[5,<em><strong>4</strong></em>,4,7,<em><strong>6</strong></em>,11,11] 变为 [5,4,7,11,11]\n- 步骤 3 ：[5,<em><strong>4</strong></em>,7,11,11] 变为 [5,7,11,11]\n[5,7,11,11] 是一个非递减数组，因此，返回 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [4,5,7,7,13]\n<strong>输出：</strong>0\n<strong>解释：</strong>nums 已经是一个非递减数组，因此，返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                "Notice that an element will be removed if and only if there exists a strictly greater element to the left of it in the array.",
                "For each element, we need to find the number of rounds it will take for it to be removed. The answer is the maximum number of rounds for all elements. Build an array dp to hold this information where the answer is the maximum value of dp.",
                "Use a stack of the indices. While processing element nums[i], remove from the stack all the indices of elements that are smaller than nums[i]. dp[i] should be set to the maximum of dp[i] + 1 and dp[removed index]."
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