leetcode-problemset/leetcode-cn/originData/sorted-merge-lcci.json

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        "question": {
            "questionId": "1000012",
            "questionFrontendId": "面试题 10.01",
            "categoryTitle": "LCCI",
            "boundTopicId": 91671,
            "title": "Sorted Merge LCCI",
            "titleSlug": "sorted-merge-lcci",
            "content": "<p>You are given two sorted arrays, A and B, where A has a large enough buffer at the end to hold B. Write a method to merge B into A in sorted order.</p>\r\n\r\n<p>Initially the number of elements in A and B are&nbsp;<em>m</em>&nbsp;and&nbsp;<em>n</em> respectively.</p>\r\n\r\n<p><strong>Example:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong>\r\nA = [1,2,3,0,0,0], m = 3\r\nB = [2,5,6],       n = 3\r\n\r\n<strong>Output:</strong>&nbsp;[1,2,2,3,5,6]</pre>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>A.length == n + m</code></li>\r\n</ul>\r\n",
            "translatedTitle": "合并排序的数组",
            "translatedContent": "<p>给定两个排序后的数组 A 和 B，其中 A 的末端有足够的缓冲空间容纳 B。 编写一个方法，将 B 合并入 A 并排序。</p>\n\n<p>初始化&nbsp;A 和 B 的元素数量分别为&nbsp;<em>m</em> 和 <em>n</em>。</p>\n\n<p><strong>示例:</strong></p>\n\n<pre><strong>输入:</strong>\nA = [1,2,3,0,0,0], m = 3\nB = [2,5,6],       n = 3\n\n<strong>输出:</strong>&nbsp;[1,2,2,3,5,6]</pre>\n\n<p><strong>说明:</strong></p>\n\n<ul>\n\t<li><code>A.length == n + m</code></li>\n</ul>\n",
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                {
                    "name": "Array",
                    "slug": "array",
                    "translatedName": "数组",
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                    "translatedName": "双指针",
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                    "code": "class Solution {\npublic:\n    void merge(vector<int>& A, int m, vector<int>& B, int n) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def merge(self, A, m, B, n):\n        \"\"\"\n        :type A: List[int]\n        :type m: int\n        :type B: List[int]\n        :type n: int\n        :rtype: None Do not return anything, modify A in-place instead.\n        \"\"\"",
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                    "code": "class Solution:\n    def merge(self, A: List[int], m: int, B: List[int], n: int) -> None:\n        \"\"\"\n        Do not return anything, modify A in-place instead.\n        \"\"\"",
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                    "code": "/**\n * @param {number[]} A\n * @param {number} m\n * @param {number[]} B\n * @param {number} n\n * @return {void} Do not return anything, modify A in-place instead.\n */\nvar merge = function(A, m, B, n) {\n\n};",
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                    "lang": "TypeScript",
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                    "code": "/**\n Do not return anything, modify A in-place instead.\n */\nfunction merge(A: number[], m: number, B: number[], n: number): void {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $A\n     * @param Integer $m\n     * @param Integer[] $B\n     * @param Integer $n\n     * @return NULL\n     */\n    function merge(&$A, $m, $B, $n) {\n\n    }\n}",
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                    "code": "# @param {Integer[]} a\n# @param {Integer} m\n# @param {Integer[]} b\n# @param {Integer} n\n# @return {Void} Do not return anything, modify A in-place instead.\ndef merge(a, m, b, n)\n\nend",
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            "hints": [
                "尝试从数组的末端向前端移动。"
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