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"data": {
"question": {
"questionId": "1093",
"questionFrontendId": "1028",
"categoryTitle": "Algorithms",
"boundTopicId": 3649,
"title": "Recover a Tree From Preorder Traversal",
"titleSlug": "recover-a-tree-from-preorder-traversal",
"content": "<p>We run a&nbsp;preorder&nbsp;depth-first search (DFS) on the <code>root</code> of a binary tree.</p>\n\n<p>At each node in this traversal, we output <code>D</code> dashes (where <code>D</code> is the depth of this node), then we output the value of this node.&nbsp; If the depth of a node is <code>D</code>, the depth of its immediate child is <code>D + 1</code>.&nbsp; The depth of the <code>root</code> node is <code>0</code>.</p>\n\n<p>If a node has only one child, that child is guaranteed to be <strong>the left child</strong>.</p>\n\n<p>Given the output <code>traversal</code> of this traversal, recover the tree and return <em>its</em> <code>root</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/04/08/recover-a-tree-from-preorder-traversal.png\" style=\"width: 320px; height: 200px;\" />\n<pre>\n<strong>Input:</strong> traversal = &quot;1-2--3--4-5--6--7&quot;\n<strong>Output:</strong> [1,2,5,3,4,6,7]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/04/11/screen-shot-2019-04-10-at-114101-pm.png\" style=\"width: 256px; height: 250px;\" />\n<pre>\n<strong>Input:</strong> traversal = &quot;1-2--3---4-5--6---7&quot;\n<strong>Output:</strong> [1,2,5,3,null,6,null,4,null,7]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/04/11/screen-shot-2019-04-10-at-114955-pm.png\" style=\"width: 276px; height: 250px;\" />\n<pre>\n<strong>Input:</strong> traversal = &quot;1-401--349---90--88&quot;\n<strong>Output:</strong> [1,401,null,349,88,90]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the original tree is in the range <code>[1, 1000]</code>.</li>\n\t<li><code>1 &lt;= Node.val &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
"translatedTitle": "从先序遍历还原二叉树",
"translatedContent": "<p>我们从二叉树的根节点 <code>root</code>&nbsp;开始进行深度优先搜索。</p>\n\n<p>在遍历中的每个节点处,我们输出&nbsp;<code>D</code>&nbsp;条短划线(其中&nbsp;<code>D</code>&nbsp;是该节点的深度),然后输出该节点的值。(<em>如果节点的深度为 <code>D</code>,则其直接子节点的深度为 <code>D + 1</code>。根节点的深度为 <code>0</code>)。</em></p>\n\n<p>如果节点只有一个子节点,那么保证该子节点为左子节点。</p>\n\n<p>给出遍历输出&nbsp;<code>S</code>,还原树并返回其根节点&nbsp;<code>root</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/04/12/recover-a-tree-from-preorder-traversal.png\" style=\"height: 200px; width: 320px;\"></strong></p>\n\n<pre><strong>输入:</strong>&quot;1-2--3--4-5--6--7&quot;\n<strong>输出:</strong>[1,2,5,3,4,6,7]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/04/12/screen-shot-2019-04-10-at-114101-pm.png\" style=\"height: 250px; width: 256px;\"></strong></p>\n\n<pre><strong>输入:</strong>&quot;1-2--3---4-5--6---7&quot;\n<strong>输出:</strong>[1,2,5,3,null,6,null,4,null,7]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/04/12/screen-shot-2019-04-10-at-114955-pm.png\" style=\"height: 250px; width: 276px;\"></p>\n\n<pre><strong>输入:</strong>&quot;1-401--349---90--88&quot;\n<strong>输出:</strong>[1,401,null,349,88,90]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>原始树中的节点数介于 <code>1</code> 和 <code>1000</code> 之间。</li>\n\t<li>每个节点的值介于 <code>1</code> 和 <code>10 ^ 9</code> 之间。</li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public TreeNode recoverFromPreorder(String traversal) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def recoverFromPreorder(self, traversal):\n \"\"\"\n :type traversal: str\n :rtype: TreeNode\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\nstruct TreeNode* recoverFromPreorder(char* traversal) {\n \n}",
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"lang": "JavaScript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {string} traversal\n * @return {TreeNode}\n */\nvar recoverFromPreorder = function(traversal) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction recoverFromPreorder(traversal: string): TreeNode | null {\n \n};",
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"lang": "Swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func recoverFromPreorder(_ traversal: String) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun recoverFromPreorder(traversal: String): TreeNode? {\n\n }\n}",
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"lang": "Go",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc recoverFromPreorder(traversal string) *TreeNode {\n\n}",
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"lang": "Ruby",
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{
"lang": "Racket",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (recover-from-preorder traversal)\n (-> string? (or/c tree-node? #f))\n )",
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"Do an iterative depth first search, parsing dashes from the string to inform you how to link the nodes together."
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