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leetcode-problemset/leetcode-cn/originData/reach-a-number.json

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{
"data": {
"question": {
"questionId": "755",
"questionFrontendId": "754",
"categoryTitle": "Algorithms",
"boundTopicId": 1725,
"title": "Reach a Number",
"titleSlug": "reach-a-number",
"content": "<p>You are standing at position <code>0</code> on an infinite number line. There is a destination at position <code>target</code>.</p>\n\n<p>You can make some number of moves <code>numMoves</code> so that:</p>\n\n<ul>\n\t<li>On each move, you can either go left or right.</li>\n\t<li>During the <code>i<sup>th</sup></code> move (starting from <code>i == 1</code> to <code>i == numMoves</code>), you take <code>i</code> steps in the chosen direction.</li>\n</ul>\n\n<p>Given the integer <code>target</code>, return <em>the <strong>minimum</strong> number of moves required (i.e., the minimum </em><code>numMoves</code><em>) to reach the destination</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> target = 2\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nOn the 1<sup>st</sup> move, we step from 0 to 1 (1 step).\nOn the 2<sup>nd</sup> move, we step from 1 to -1 (2 steps).\nOn the 3<sup>rd</sup> move, we step from -1 to 2 (3 steps).\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> target = 3\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nOn the 1<sup>st</sup> move, we step from 0 to 1 (1 step).\nOn the 2<sup>nd</sup> move, we step from 1 to 3 (2 steps).\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>-10<sup>9</sup> &lt;= target &lt;= 10<sup>9</sup></code></li>\n\t<li><code>target != 0</code></li>\n</ul>\n",
"translatedTitle": "到达终点数字",
"translatedContent": "<p>在一根无限长的数轴上,你站在<code>0</code>的位置。终点在<code>target</code>的位置。</p>\n\n<p>你可以做一些数量的移动 <code>numMoves</code> :</p>\n\n<ul>\n\t<li>每次你可以选择向左或向右移动。</li>\n\t<li>第 <code>i</code>&nbsp;次移动(从 &nbsp;<code>i == 1</code>&nbsp;开始,到&nbsp;<code>i == numMoves</code> ),在选择的方向上走 <code>i</code>&nbsp;步。</li>\n</ul>\n\n<p>给定整数&nbsp;<code>target</code> ,返回 <em>到达目标所需的 <strong>最小&nbsp;</strong>移动次数(即最小 <code>numMoves</code> )&nbsp;</em>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> target = 2\n<strong>输出:</strong> 3\n<strong>解释:</strong>\n第一次移动从 0 到 1 。\n第二次移动从 1 到 -1 。\n第三次移动从 -1 到 2 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> target = 3\n<strong>输出:</strong> 2\n<strong>解释:</strong>\n第一次移动从 0 到 1 。\n第二次移动从 1 到 3 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>-10<sup>9</sup>&nbsp;&lt;= target &lt;= 10<sup>9</sup></code></li>\n\t<li><code>target != 0</code></li>\n</ul>\n",
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