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"question": {
"questionId": "767",
"questionFrontendId": "762",
"categoryTitle": "Algorithms",
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"title": "Prime Number of Set Bits in Binary Representation",
"titleSlug": "prime-number-of-set-bits-in-binary-representation",
"content": "<p>Given two integers <code>left</code> and <code>right</code>, return <em>the <strong>count</strong> of numbers in the <strong>inclusive</strong> range </em><code>[left, right]</code><em> having a <strong>prime number of set bits</strong> in their binary representation</em>.</p>\n\n<p>Recall that the <strong>number of set bits</strong> an integer has is the number of <code>1</code>&#39;s present when written in binary.</p>\n\n<ul>\n\t<li>For example, <code>21</code> written in binary is <code>10101</code>, which has <code>3</code> set bits.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> left = 6, right = 10\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>\n6 -&gt; 110 (2 set bits, 2 is prime)\n7 -&gt; 111 (3 set bits, 3 is prime)\n8 -&gt; 1000 (1 set bit, 1 is not prime)\n9 -&gt; 1001 (2 set bits, 2 is prime)\n10 -&gt; 1010 (2 set bits, 2 is prime)\n4 numbers have a prime number of set bits.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> left = 10, right = 15\n<strong>Output:</strong> 5\n<strong>Explanation:</strong>\n10 -&gt; 1010 (2 set bits, 2 is prime)\n11 -&gt; 1011 (3 set bits, 3 is prime)\n12 -&gt; 1100 (2 set bits, 2 is prime)\n13 -&gt; 1101 (3 set bits, 3 is prime)\n14 -&gt; 1110 (3 set bits, 3 is prime)\n15 -&gt; 1111 (4 set bits, 4 is not prime)\n5 numbers have a prime number of set bits.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= left &lt;= right &lt;= 10<sup>6</sup></code></li>\n\t<li><code>0 &lt;= right - left &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
"translatedTitle": "二进制表示中质数个计算置位",
"translatedContent": "<p>给你两个整数&nbsp;<code>left</code>&nbsp;和&nbsp;<code>right</code> ,在闭区间 <code>[left, right]</code>&nbsp;范围内,统计并返回 <strong>计算置位位数为质数</strong> 的整数个数。</p>\n\n<p><strong>计算置位位数</strong> 就是二进制表示中 <code>1</code> 的个数。</p>\n\n<ul>\n\t<li>例如, <code>21</code>&nbsp;的二进制表示&nbsp;<code>10101</code>&nbsp;有 <code>3</code> 个计算置位。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>left = 6, right = 10\n<strong>输出:</strong>4\n<strong>解释:</strong>\n6 -&gt; 110 (2 个计算置位2 是质数)\n7 -&gt; 111 (3 个计算置位3 是质数)\n9 -&gt; 1001 (2 个计算置位2 是质数)\n10-&gt; 1010 (2 个计算置位2 是质数)\n共计 4 个计算置位为质数的数字。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>left = 10, right = 15\n<strong>输出:</strong>5\n<strong>解释:</strong>\n10 -&gt; 1010 (2 个计算置位, 2 是质数)\n11 -&gt; 1011 (3 个计算置位, 3 是质数)\n12 -&gt; 1100 (2 个计算置位, 2 是质数)\n13 -&gt; 1101 (3 个计算置位, 3 是质数)\n14 -&gt; 1110 (3 个计算置位, 3 是质数)\n15 -&gt; 1111 (4 个计算置位, 4 不是质数)\n共计 5 个计算置位为质数的数字。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= left &lt;= right &lt;= 10<sup>6</sup></code></li>\n\t<li><code>0 &lt;= right - left &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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